java - 如何查看字符串的第一个字符是否是某个字符，如果是，则执行操作(无法正常工作)

Question

import java.util.Random;
import java.util.Scanner;

public class MineSweeper {

public static void main(String[] args) {
    Scanner scnr = new Scanner(System.in);
    boolean playAgain = true;

    System.out.println("Welcome to Mine Sweeper!");

while (playAgain)   {
    final int MIN_SIZE = 3;
    final int MAX_SIZE = 20;
    final char NO_NEARBY_MINE = ' ';

    String errorWidth = "Expected a number from " + MIN_SIZE + " to " + MAX_SIZE + "\nWhat width of map would you like (" + MIN_SIZE + "-" + MAX_SIZE + "):";
    String errorHeight = "Expected a number from " + MIN_SIZE + " to " + MAX_SIZE + "\nWhat height of map would you like (" + MIN_SIZE + "-" + MAX_SIZE + "):";

    System.out.println("What width of map would you like (" + MIN_SIZE + "-" + MAX_SIZE + "):");
    int userWidth = promptUser(scnr, errorWidth, MIN_SIZE, MAX_SIZE);
    System.out.println("What height of map would you like (" + MIN_SIZE + "-" + MAX_SIZE + "):");
    int userHeight = promptUser(scnr, errorHeight, MIN_SIZE, MAX_SIZE);

    String errorGetRow = "Expected a number from " + 1 + " to " + userWidth + ".";
    String errorGetCol = "Expected a number from " + 1 + " to " + userHeight + ".";
    int minRowCol = 1;

    char[][] mineArray = new char[userHeight][userWidth];
    eraseMap(mineArray);
    simplePrintMap(mineArray);

    System.out.println("row: ");
    int row = promptUser(scnr, errorGetRow, minRowCol, userWidth);
    System.out.println("column: ");
    int column = promptUser(scnr, errorGetCol, minRowCol, userHeight);
    mineArray[row-1][column-1] = NO_NEARBY_MINE;
    simplePrintMap(mineArray);

    System.out.println("Would you like to play again (y/n)?");
    String response = scnr.next();
    if (response.startsWith("Y") || response.startsWith("y")) {
            playAgain = true;
    }
    else {
        playAgain = false;
    }

    }
System.out.println("Thank you for playing Mine Sweeper!");
}

public static int promptUser(Scanner in, String prompt, int min, int max) {
    int userTempVal = 0;

        do {
        userTempVal = in.nextInt();
            if (userTempVal < min || userTempVal > max) {
            System.out.println(prompt);
            }

       }while (userTempVal < min || userTempVal > max);

    return userTempVal; 
    }

public static void eraseMap(char[][] map) {
    final char UNSWEPT = '.';
    for (int row = 0; row < map.length; row++) {
        for (int col = 0; col < map[row].length; col++) {
            map[row][col] = UNSWEPT;
        }
    }
    return;
}    

public static void simplePrintMap(char[][] map) {
    for (int row = 0; row < map.length; row++) {
        for (int col = 0; col < map[row].length; col++) {
            System.out.print(map[row][col] + " ");
        }
        System.out.println("");
    }
    return; //FIXME
}

编辑:因此，我更改了代码以使用 .equals 而不是 ==，并且当我输入只有一个单词的字符串时，我的代码可以成功运行，因此"is"。如果我输入一串多个单词(“是的，我愿意”)，我仍然会收到错误。输入包含多个单词的字符串会产生错误。当我使用 scnr 时。 next() 时，它总是编译 else 语句，即使该语句是“是的，我愿意”，其中第一个字母是 Y。如果我使用 scnr 。 nextLine() 它编译 if 语句，重新启动循环，打印“ map 的宽度...”，然后在我输入任何内容之前给出错误。

我主要指的是底部的main方法，从“你想再玩一次吗”到main方法的末尾。我的提示用户方法也有问题，我希望该方法显示错误消息，并在用户输入除 int 之外的任何内容时再次扫描 int。

Answer 1

使用response.equals()而不是==。

== 比较对象的引用，而 equals() 会比较字符串的值。