gpt4 book ai didi

java - try/catch block 中带有 Scanner 的 NoSuchElementException

转载 作者:行者123 更新时间:2023-12-01 20:03:05 25 4
gpt4 key购买 nike

对于具有两种可能的游戏模式的简单迷宫游戏,我尝试在游戏开始时实现扫描仪,然后使用扫描仪询问玩家的姓名。我决定创建一个类 MenuParser,在其中我想使用接受对象并将它们传递给各自方法的静态方法。

出于某种原因,Java 不断返回相同的错误:

Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Unknown Source) at java.util.Scanner.next(Unknown Source) at java.util.Scanner.nextInt(Unknown Source) at java.util.Scanner.nextInt(Unknown Source) at game.MenuParser.startUpMenu(MenuParser.java:26) at game.MainProgram.main(MainProgram.java:18)

我研究过类似的问题(例如 this onethis one ),了解如何处理从 try/catch block 返回值以及导致 NoSuchElementException 的原因扫描仪,但我似乎无法弄清楚。我尝试移动我的 return 并简化 Scanner(例如,通过简单地删除 try/catch block ),但都没有解决问题。

任何帮助将不胜感激。

主要方法如下:

package game;

import world.Maze;

public class MainProgram {

public static void main(String[] args) {

// Initialize objects concerned with playing the game
Player myPlayer = new Player();
Maze myMaze = new Maze();

// Print welcome message and ask the player for his/her name
System.out.println("Hi there! Welcome to this maze game in Java by MV. \n");
myPlayer.setPlayerNameWithScanner();

// Ask the player which game mode he/she would like to play: single player or multiplayer?
int choice = MenuParser.startUpMenu();
System.out.println(choice);
// Parse input and depending on the answer initialize the corresponding menu to start the game
}

}

MenuParser 类如下所示:

package game;

import java.util.InputMismatchException;
import java.util.Scanner;

public class MenuParser {

public static void pause() {

System.out.println("Please hit enter to continue.");
Scanner hitEnter = new Scanner(System.in);
hitEnter.nextLine();
hitEnter.close();
}

public static int startUpMenu() {

int choice = 0;

System.out.println("Which game mode would you like to play?" + "\n");
System.out.println("\t 1. Single player.");
System.out.println("\t 2. Robot.");

try(Scanner startUp = new Scanner(System.in)){

choice = startUp.nextInt();
System.out.println(choice);

if(choice != 1 || choice != 2) {

System.out.println("Sorry, this is not a valid choice.");
startUpMenu();
}
}
catch(InputMismatchException im) {

System.out.println("Sorry, it seems the input is of wrong type.");
startUpMenu();
}
return choice;
}
}

Player 类如下所示:

package game;

import java.util.InputMismatchException;
import java.util.Scanner;

public class Player {

private String playerName;
private int playerStepScore;

public Player () {
}

public void setPlayerNameWithScanner(){

System.out.println("Please enter your name. \n");

try(Scanner playerNameScanner = new Scanner(System.in);){

String playerName = playerNameScanner.nextLine();
setPlayerName(playerName);
}
catch(InputMismatchException im) {
System.out.println("Input seems to be wrong");
setPlayerNameWithScanner();
}
}

public String getPlayerName() {
return playerName;
}
public void setPlayerName(String playerName) {
this.playerName = playerName;
}
public int getPlayerStepScore() {
return playerStepScore;
}
public void setPlayerStepScore(int playerStepScore) {
this.playerStepScore = playerStepScore;
}


}

之前的 main 方法(使用了多个扫描器,包括 try-with-recources,没有任何错误或异常)如下所示:

package game;

import java.util.Scanner;
import java.io.FileNotFoundException;
import java.io.FileReader;
import game.Cell;
import game.Maze;
import game.Border;

public class Program {

public static void main(String[] args) {

/*
* General variables that will be used throughout the loops
* that follow; maxXCoor and maxYCoor are used as maximum values
* to initialize a grid of a certain size; myMaze is a Maze object
* which is needed to access its methods throughout the loops.
*/
int maxXCoor = 0;
int maxYCoor = 0;
Maze myMaze = new Maze();

/*
* A Scanner is invoked to simply deal with the entry
* of the file name; this location is then saved in the
* variable fileName, which is then passed onto the next
* Scanner and FileReader.
*/
System.out.println("Please enter a file name");
Scanner scan = new Scanner(System.in);
String fileName = scan.nextLine();
scan.close();
System.out.println(fileName);

/*
* This first block is used to scan the entire input file
* and look for maxXCoor and maxYCoor to initialize the grid.
*/
try(Scanner input = new Scanner(new FileReader(fileName));){

int count = 1;
while(input.hasNextLine()) {

/*
* Every line is read as a String which is then
* split using a comma as the delimiter. Every
* part that is delimited by a comma is then put into an
* array called words.
*/
String line = input.nextLine();
String[] words = line.split(",");

/*
* Basic sanity check to make sure the input file uses
* the template which was agreed upon, where the first line
* are just headers.
*/
if(count == 1) {

if(!(words[0].toLowerCase()).equals("xcoordinate")) {

System.out.println("It looks like there is an issue with the template of your input file.");
System.out.println("Please check your input file and try again!");
System.exit(0);
}
}
/*
* Once we're not at line one anymore, we can start checking
* the current coordinates, xCoor and yCoor, against
* the maximum coordinates, maxXCoor and maxYCoor.
*/
else {

int xCoor = Integer.parseInt(words[0]);
int yCoor = Integer.parseInt(words[1]);

if(xCoor > maxXCoor) {

maxXCoor = xCoor;
}
if(yCoor > maxYCoor) {

maxYCoor = yCoor;
}
}
count++;
}
}
catch(FileNotFoundException fe) {
System.out.println("File not found");
System.exit(0);
}

/*
* As Java uses zero-indexing, we will want to
* augment the values of our maximum coordinates
* by one, to avoid IndexOutOfBoundsExceptions in
* the future. After that we initialize a 2D array
* of type Cell with these coordinates.
*/
maxXCoor++;
maxYCoor++;
Cell[][] myGrid = new Cell[maxXCoor][maxYCoor];


try(Scanner input = new Scanner(new FileReader(fileName));){

int count = 1;
while(input.hasNextLine()) {

String line = input.nextLine();
String[] words = line.split(",");

if(count > 1) {

int xCoor = Integer.parseInt(words[0]);
int yCoor = Integer.parseInt(words[1]);
Border borderNorth = new Border(words[2]);
Border borderSouth = new Border(words[3]);
Border borderEast = new Border(words[4]);
Border borderWest = new Border(words[5]);
Cell myCell = new Cell(borderNorth,borderSouth,borderEast,borderWest);
myGrid[xCoor][yCoor] = myCell;

}
count++;
}
}
catch(FileNotFoundException fe) {
System.out.println("File not found");
System.exit(0);
}

for(int x = maxXCoor-1; x >= 0; x--) {
// Draw north & south wall
for(int y = 0; y < maxYCoor; y++) {
Border myBorderNorth = myGrid[x][y].getNorthWall();
String myTypeNorth = myBorderNorth.getType();
if(myTypeNorth.equals("wall")) {
System.out.print("+---");
}
else {
System.out.print("+ ");
}
if(y == maxYCoor-1) {
System.out.println("+");
}
}
// Draw west & east wall
for(int y = 0; y < maxYCoor; y++) {
Border myBorderWest = myGrid[x][y].getWestWall();
String myTypeWest = myBorderWest.getType();
if(myTypeWest.equals("wall")) {
System.out.print("| ");
}
else {
System.out.print(" ");
}
// Draw last eastern wall
if(y == maxYCoor-1) {
System.out.println("|");
}
}
// Draw last southern wall
if(x == 0) {
for(int y = 0; y < maxYCoor; y++) {
System.out.print("+---");
}
System.out.println("+");
}
}
myMaze.setGrid(myGrid);
}

}

最佳答案

您有以下代码:

        try(Scanner startUp = new Scanner(System.in)){
//stuff
}

这称为尝试资源。当此 try block 执行完毕时,代码将自动关闭 Scanner。

但是一旦您关闭与System.in 关联的扫描程序,System.in 就会保持关闭状态。如果您尝试读取其他任何内容,即使您使用新的 Scanner ,您也会收到 NoSuchElementException 。这似乎就是这里正在发生的事情。最有可能的是,setPlayerNameWithScanner 正在以类似的方式关闭扫描仪,从而导致您出现问题。

关于java - try/catch block 中带有 Scanner 的 NoSuchElementException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47803693/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com