ios - JSON解析(快速)

Question

我正在尝试解析此JSON

["Items": <__NSSingleObjectArrayI 0x61000001ec20>(

{

    AccountBalance = 0;

    AlphabetType = 3;

    Description = "\U0631\U06cc\U0648";

    FullCode = "P_21_JIM_456_IR_25";

    IRNumber = 25;

    LeftNumber = 21;

    RightNumber = 456;

}

)

, "ErrorCode": 0, "ErrorMessage": , "Result": 1]

在这种情况下如何访问items参数？我正在尝试为Items创建结构，但出现以下错误:无法将类型'(key:String，value:AnyObject)'的值转换为预期的参数类型'[String:AnyObject]'
access Items参数的解决方案是什么？

有我的Items结构并解析JSON代码:

 struct PalletItems {

        let accountBalance : Int
        let alphabetType : Int
        let description : String
        let fullCode : String
        let irNumber : Int
        let leftNumber : Int
        let rightNumber : Int

        init? (accountBalance: Int, alphabetType: Int, description : String, fullCode: String, irNumber: Int, leftNumber: Int, rightNumber: Int ) {


            self.accountBalance = accountBalance
            self.alphabetType = alphabetType
            self.description = description
            self.fullCode = fullCode
            self.irNumber = irNumber
            self.leftNumber = leftNumber
            self.rightNumber = rightNumber

        }



func palletListFromJSONData(_ data : Data) -> PaletListResult {



        do{
            let jsonresult : [String : AnyObject]
                = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! [String:AnyObject]
            print("json : \(jsonresult)")
             let success = jsonresult["Items"] as? PalletItems
            print("items is : \(success)")

            for paletJson in jsonresult {
                if let palet = getBalanceOfWalletFromJsonObject(paletJson) {

                    finalResult.append(palet)
                }
            }


            let palet = getBalanceOfWalletFromJsonObject(jsonresult)

            finalResult.append(palet!)

            return .success(finalResult)

        }

        catch let error as NSError{
            print("that is parsing json error : \(error)")

            return .failure(error)
        }
    }


    func getBalanceOfWalletFromJsonObject(_ json: [String: AnyObject]) -> ListOfPlates?{

        guard let
            errorCode = json["ErrorCode"] as? Int,
            let errorMessage = json["ErrorMessage"] as? String,
            let result = json["Result"] as? Int,
            let item = json["Items"] as? PalletItems

            else {
                return nil
        }
        let obj = ListOfPlates(errorCode: errorCode, errorMessage: errorMessage, result: result, items: item)

        return obj
    }

Answer 1

问题是您尝试将其作为键值对进行访问，但将其作为数组获取。所以json应该是[[String:Any]]
现在，此json应该解析为json.first!给你[String:Any]。现在，您可以获得任何键的值。