java - 尝试使用嵌套循环获取非重复数字..(二维数组)

Question

我正在尝试找出一种方法，将随机数插入到 5x5 的二​​维数组中。我正在开发一款宾果游戏，因此任何人都可以帮助我，我将非常感激。我对 Java 相当陌生，所以任何帮助都会很好。谢谢。

考虑:

boolean matchFound;  // used to track when a repeat is found
int rand; // temporarily store the random number before putting it into the array to check if it's a repeat

Random rn = new Random();
for (int i = 0; i < 25 ; i++) {
    rand = rn.nextInt(15) + 1;
    matchFound = false;  // assume that the number generated is not a repeat
    for (int x = 0; x <= 5; x++) {
        for (int j = 0; j <= 5 ; ++j){
            if (rand == b[x][j]) {  // check if the number just generated is a repeat
                matchFound = true;  // if it is, set the boolean to True and use that after the loop
            }           
            if (matchFound == true) { // if the last number is a repeat, then
                i = i - 1;  // reduce the loop counter by 1 to go back to that place for the new number
            } else {
                b[i][j] = rand;  // the number was not repeated so insert it.
            }
        }
    }
}

Answer 1

我建议将其视为宾果游戏 - 您有一组数字，将它们随机化，然后为棋盘“选择”数字。我相信宾果游戏的范围是从 1 到 75？但你可以改变这一点。然后只需从 ArrayList 中选取前 25 个数字，它们肯定是随机的，不会以这种方式重复。

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;

public class Test {
    public static void main(String[] args){
        ArrayList<Integer> bingo = new ArrayList<Integer>();
        int[][] b = new int[5][5];

        // create a list in order
        for (int i = 1; i <= 75; i++) {
          bingo.add(i);
        }

        Collections.shuffle(bingo); // randomize

        // Add to the board
        for (int i = 0; i < 5; i++) {
          for (int j = 0; j < 5; j++) {
            b[i][j] = bingo.remove(0); // remove the first item in the shuffled list
          }
        }

        System.out.print(Arrays.deepToString(b));
    }
}