ios - 如何在Swift 3中将NSFormatter数字用于数组中的波斯或阿拉伯数字？

Question

我知道如何使用NSFormatter Number将英语数字转换为波斯/阿拉伯数字，但是问题是我有一个数组，并且想要将数组中的所有数字转换为波斯/阿拉伯数字。

我怎样才能做到这一点？
请帮忙。

这是一个数字的代码:

let numberFormatter = NumberFormatter()
    numberFormatter.locale = Locale(identifier: "fa")
    numberFormatter.numberStyle = NumberFormatter.Style.decimal

    numberFormatter.string(from: NSNumber(value: checkNumber))
    let persianNumber = numberFormatter.string(from: NSNumber(value: checkNumber))!

如您所见，我可以转换一个数字(checkNumber是英文数字，​​persianNumber是波斯/阿拉伯数字)

Answer 1

创建swift文件并附加此扩展名

extension String {


 func englishToPersian() -> String{
    var sum = ""
    let letters = self.characters.map { String($0) }
    for letter in letters {
        if (Int(letter) != nil) {
            let persianNumber = ["۰","۱","۲","۳","۴","۵","۶","۷","۸","۹"]
            sum = sum+persianNumber[Int("\(letter)")!]
        } else {
            sum = sum+letter
        }
    }
    return sum
 }

 func persianToEnglish() -> String{
    var sum = ""
    let letters = self.characters.map { String($0) }
    let persianNumber = ["۰","۱","۲","۳","۴","۵","۶","۷","۸","۹"]
    for letter in letters {
        for (index, element) in persianNumber.enumerated() {
            if letter == element {
                sum = sum + "\(index)"
            }
        }
    }
    return sum
 }

}

使用这个😊

let strEnglish1 = "1234567890"
strEnglish1.englishToPersian() // ۱۲۳۴۵۶۷۸۹۰

let strEnglish2 = "1200 toman"
strEnglish2.englishToPersian() // ۱۲۰۰ toman

let strPersian1 = "۱۲۳۴۵۶۷۸۹۰"
strPersian1.persianToEnglish() // 1234567890

let strPersian2 = "۱۲۰۰  تومان"
strPersian1.persianToEnglish() // ۱۲۰۰  تومان