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java - Smack XMPP Java : How to access the original XML reprsentation of a ByteStreamRequest (OPEN)?

转载 作者:行者123 更新时间:2023-12-01 19:49:57 24 4
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我需要访问字节流初始化的原始 XML 表示,因为我需要与自定义实现进行通信。 toXML 方法只是重建 XMLStrutur。

我已经尝试使用订阅实现来实现自定义调试器,但 StreamElement 也不包含原始发送的 XML 数据。

最佳答案

通过实现订阅调试器来解决,该调试器可以将原始 XML 日志转发到监听器。示例:

公共(public)类 SubscribeDebugger 扩展了 SmackDebugger {

private static List<IncomingRequestDebugListener> incomingRequestDebugListeners = new ArrayList<>();
private static List<OutgoingRequestDebugListener> outgoingRequestDebugListeners = new ArrayList<>();
private static Boolean enableOutputToConsole;
private static SmackDebugger consoleDebugger;
private ReaderListener readerListener;
private WriterListener writerListener;
private ObservableWriter writer;
private ObservableReader reader;

public SubscribeDebugger(XMPPConnection connection) {
super(connection);
if (this.getEnableOutputToConsole()) {
consoleDebugger = new ConsoleDebugger(connection);
}
readerListener = str -> notifyIncomingRequestDebugListeners(str.toString());
writerListener = str -> notifyOutgoingRequestDebugListeners(str.toString());
}

public Boolean getEnableOutputToConsole() { return enableOutputToConsole; }
public static void setEnableOutputToConsole(Boolean active) {
enableOutputToConsole = active;
}

/*Static part since a debugger will be initiated by xmpp connection. Smack does not
provide access on the debugger instances. All instances share the listeners.*/
public static void registerIncomingRequestDebugListener (IncomingRequestDebugListener listener) {
incomingRequestDebugListeners.add(listener);
}
public static void unregisterIncomingRequestDebugListener(IncomingRequestDebugListener listener) {
incomingRequestDebugListeners.remove(listener);
}
public static void registerOutgoingRequestDebugListener (OutgoingRequestDebugListener listener) {
outgoingRequestDebugListeners.add(listener);
}
public static void unregisterOutgoingRequestDebugListener(OutgoingRequestDebugListener listener) {
outgoingRequestDebugListeners.remove(listener);
}
protected void notifyIncomingRequestDebugListeners (String streamElement) {
incomingRequestDebugListeners.parallelStream().forEach((listener) -> {
listener.onRequestReceived(streamElement);
});
}
protected void notifyOutgoingRequestDebugListeners (String streamElement) {
outgoingRequestDebugListeners.parallelStream().forEach((listener) -> {
listener.onRequestSent(streamElement);
});
}

@Override
public void userHasLogged(EntityFullJid user) {

}

@Override
public Reader newConnectionReader(Reader reader) {


ObservableReader debugReader = new ObservableReader(reader);
debugReader.addReaderListener(readerListener);
reader = debugReader;

if (enableOutputToConsole && consoleDebugger != null)
return consoleDebugger.newConnectionReader(reader);
return reader;
}

@Override
public Writer newConnectionWriter(Writer writer) {
if(enableOutputToConsole && consoleDebugger != null)
return consoleDebugger.newConnectionWriter(writer);
return writer;
}

@Override
public void onIncomingStreamElement(TopLevelStreamElement streamElement) {
if(enableOutputToConsole && consoleDebugger != null)
consoleDebugger.onIncomingStreamElement(streamElement);


}

@Override
public void onOutgoingStreamElement(TopLevelStreamElement streamElement) {
if (enableOutputToConsole && consoleDebugger != null)
consoleDebugger.onOutgoingStreamElement(streamElement);

}

}

关于java - Smack XMPP Java : How to access the original XML reprsentation of a ByteStreamRequest (OPEN)?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59094778/

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