Java，以数字开头的单词

Question

这个问题已经有答案了:

What is a debugger and how can it help me diagnose problems? (3 个回答)

已关闭 4 年前。

我想知道为什么计数不返回除 0 之外的任何内容。我想知道是否可以在没有数组的情况下完成，这意味着这种方式。感谢帮助，谢谢!

    String word= "";
    int value = 0;

    while(!word.equalsIgnoreCase("Exit")){
        System.out.print("Type words or exit to quit: ");
        word = scan.nextLine();


    } 
        value = numberCount(word);
        System.out.print("The number of words that start with a number is "+value);
}
    public static int numberCount(String str){
        int count =0;
        char c = str.charAt(0);
        if(c >= '0' && c <= '9'){
            count++;
        }
        return count;
    }

}

Answer 1

问题是您只在循环之外调用该方法。 (当 word 将作为退出条件时，"Exit"，它不以数字开头)这使得您的程序将始终打印 0。使用您的计数器变量并将方法调用移动到循环内，以便检查输入的每个单词:

while(!word.equalsIgnoreCase("Exit")){
    System.out.print("Type words or exit to quit: ");
    word = scan.nextLine();
    value += numberCount(word);
}   
System.out.print("The number of words that start with a number is "+value);

输入/输出示例:

Type words or exit to quit: 2foo
Type words or exit to quit: foo
Type words or exit to quit: 3foo
Type words or exit to quit: 10foo
Type words or exit to quit: Exit
The number of words that start with a number is 3