java - Bukkit 插件踢原因仅使用第一个单词

Question

所以我正在为我的服务器创建一个踢/禁止命令，格式为/踢名称原因。我一切正常，但 原因 只能是 1 个单词，除此之外的任何内容，例如 /kick BattleDash hello world 会说 BattleDash 因 被踢你好。

这是我的代码:

    if (cmd.getName().equalsIgnoreCase("kick") && sender instanceof Player) {

        Player player = (Player) sender;

        int length = args.length;

        if (length >= 2) {

            boolean playerFound = false;

            for (Player playerToKick : Bukkit.getServer().getOnlinePlayers()) {
                if(playerToKick.getName().equalsIgnoreCase(args[0])) {
                    playerToKick.kickPlayer(ChatColor.RED + "Kicked by Administrator " + player.getName() + "\nReason: " + args[1]);
                    player.sendMessage(ChatColor.RED + "[BATTLEDASHLOGS]: Kicked player " + playerToKick.getName() + "succesfully!");
                    break;
                }
            }

            if (playerFound == false) {
                player.sendMessage(ChatColor.RED + "[BATTLEDASHLOGS]: " + args[0] + " was not found!");
            }

        } else player.sendMessage(ChatColor.RED + "[BATTLEDASHLOGS]: Incorrect arguments!" + ChatColor.RED + " /kick <PlayerName> <reason>");

    return true;

}

(此外，如果您不包含原因，则会在聊天中给出内部错误并在控制台中发生异常)

Answer 1

您的代码由于其编程方式而这样做。

如果我们看一下接受参数的行:

playerToKick.kickPlayer(ChatColor.RED + "Kicked by Administrator " + player.getName() + "\nReason: " + args[1]);

我们可以看到您仅使用args[1]。如果我们将消息视为数组，问题就很清楚了:

在位置 0(记住数组从 0 开始):BattleDash

1:你好

2:世界

当您在消息中仅使用 args[1] 时，将仅使用 hello!相反，我们需要做的是使用所有参数。一种方法是这样的:

// First, transform your array into a list, so it's easier to understand
List<String> arguments = new ArrayList<>(args);

String playerName = arguments.get(0);  // Get the player name
arguments.remove(0);   // Remove the player name from our arguments list, we don't want it in the message

String message = String.join(" ", arguments);  // Combine all the other arguments into a message