java - 当嵌套 JSON 中出现相同字段名称时，将 JSON 解析为 java 对象

Question

下面是我的 JSON:

{
  "time":{
    "date":{
      "year":2017,
      "month":3,
      "day":12
     },
    "time":{
      "hour":10,
      "minute":42,
      "second":42,
      "nano":810000000
     }
   },
"name":"Jon",
"message":{
"product":"orange"
"price":2000
}
}

“时间”字段有一个嵌套的“时间”字段。我如何使用 jackson 解析它到 java 对象。谁能告诉我正确的方法吗？

Answer 1

您可以创建如下类:

class JavaObject {
    private TimeObject time;
    private String name;
    //other fields
    //getters and setters
}

class TimeObject {
    private Date date;
    private Time time;
    //getters and setters
}

class Date {
    private int year;
    private int month;
    private int day;
    //getters and setters
}

class Time {
    private int hour;
    private int minute;
    private int second;
    private long nano;
    //getters and setters
}

完成后，您可以使用Jackson将json字符串反序列化为JavaObject对象，例如:

ObjectMapper objectMapper = new ObjectMapper();
JavaObject javaObject = objectMapper.readValue("{\n" + 
        "  \"time\":{\n" + 
        "    \"date\":{\n" + 
        "      \"year\":2017,\n" + 
        "      \"month\":3,\n" + 
        "      \"day\":12\n" + 
        "     },\n" + 
        "    \"time\":{\n" + 
        "      \"hour\":10,\n" + 
        "      \"minute\":42,\n" + 
        "      \"second\":42,\n" + 
        "      \"nano\":810000000\n" + 
        "     }\n" + 
        "   },\n" + 
        "\"name\":\"Jon\"}", JavaObject.class);
System.out.println(javaObject);