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java - java中使用dfs和bfs查找计算机上最大的文件

转载 作者:行者123 更新时间:2023-12-01 19:35:58 25 4
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我最近在一个类项目上遇到了一些麻烦,确实需要一些帮助。我的老师希望全类同学创建一个用 java 编写的程序,该程序将使用深度优先搜索 (DFS) 定位计算机上最大的文件(具有最长路径的文件),并使用广度优先搜索 (BFS) 创建一个单元测试,以确保我们实际上找到了最大的文件。我尝试研究几个网站来帮助我解决问题,但进展甚微,而且随着截止日期的临近,我开始变得绝望。我会接受任何提供的帮助,谢谢。

编辑:我的老师也提供了这个。

包 edu.gcccd.csis;

import java.io.File;
import java.nio.file.Path;
import java.nio.file.Paths;


/**
* Finds the largest file using DFS.
*/
public class Finder {


/**
* If no start location is given, the we start the search in the current dir
*
* @param args {@link String}[] start location for the largest file search.
*/
public static void main(final String[] args) {
final Path path = Paths.get(args.length < 1 ? "." : args[0]);
final File ex = findExtremeFile(path);
System.out.printf("Starting at : %s, the largest file was found here:\n%s\n its size is: %d\n",
path.toAbsolutePath().toString(),
ex.getAbsolutePath(),
ex.length());
}


/**
* Identifies the more extreem of two given files.
* Modifying this method allows to search for other extreems, like smallest, oldest, etc.
*
* @param f1 {@link File} 1st file
* @param f2 {@link File} 2nd file
* @return {@link File} the more extreme of the two given files.
*/
static File extreme(final File f1, final File f2) {
// ...
}


/**
* DFS for the most extreme file, starting the search at a given directory path.
*
* @param p {@link Path} path to a directory
* @return {@link File} most extreme file in the given path
*/
static File findExtremeFile(final Path p) {
File x = null;
final File[] fa = p.toFile().listFiles();
if (fa != null) { // if null then directory is probably not accessible
//
// Since this is DFS, first find all sub-directories in the current directory
//


..
//
// Now let's look at al the files in the current dir
//
..
}
return x;
}
}

///////////////和这个////////////////////////////////////////////////////////

包 edu.gcccd.csis;

import org.junit.Test;


import java.io.File;
import java.io.FileWriter;
import java.nio.file.Path;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;


import static org.junit.Assert.assertEquals;


public class FinderTest {


/**
* BFS implementation to find extreme file
*
* @param p {@link Path} starting path
* @return {@link File} extreme file
*/
@SuppressWarnings({"unchecked"})
private static File findExtremeFile(final Path p) {
final List fileList = new ArrayList();
fileList.add(p.toFile());


...




return x;
}




/**
* Verify that the extreme method identifies the largest etc etc. file
*/
@Test
public void testExtreme() throws Exception {
// check what happens if one file is null ..
File f1 = null;
final File f2 = File.createTempFile("test2_", ".tmp");
f2.deleteOnExit();


assertEquals(f2, Finder.extreme(f1, f2));
assertEquals(f2, Finder.extreme(f2, f1));


// check what happens if both files have the same length (like 0)




...




// check what happens if one file is larger
// .. how to add content to a (tmp-)file:
// https://www.baeldung.com/java-write-to-file




...


assertEquals(f2, Finder.extreme(f2, f1));
assertEquals(f2, Finder.extreme(f1, f2));
}


/**
* Verify that DFS and BFS return the same result.
*/
@Test
public void findExtremeFile() throws Exception {
// find a reasonable place to start the search .. or hard code is this doesn't work
final File f2 = File.createTempFile("test", ".tmp");
f2.deleteOnExit();


final Path p = f2.getParentFile().getParentFile().toPath();
final File extreme1 = Finder.findExtremeFile(p);
final File extreme2 = FinderTest.findExtremeFile(p);
assertEquals(extreme1, extreme2);
}
}

最佳答案

这是让您开始的一个开始。请注意评论:

import java.io.File;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.LinkedList;

/**
* Finds the largest file using DFS.
*/
public class Finder {

/**
* If no start location is given, the we start the search in the current dir
*
* @param args {@link String}[] start location for the largest file search.
*/
public static void main(final String[] args) {
Path path = Paths.get(args.length < 1 ? "." : args[0]);
final File ex = findExtremeFile(path);
System.out.printf("Starting at : %s, the largest file was found here:\n%s\n its size is: %d\n",
path.toAbsolutePath().toString(),
ex.getAbsolutePath(),
ex.length());
}

/**
* Identifies the more extreme of two given files.
* Modifying this method allows to search for other extremes, like smallest, oldest, etc.
*
* @param f1 {@link File} 1st file
* @param f2 {@link File} 2nd file
* @return {@link File} the more extreme of the two given files.
*/
static File extreme(final File f1, final File f2) {

//if one file is not a valid file, return the other
if (f1 == null || !f1.exists() || !f1.isFile() ){
if (f2 != null && f2.exists() && f2.isFile()) return f2;
else throw new IllegalArgumentException();
}

if (f2 == null || !f2.exists() || !f2.isFile() ){
if (f1 != null && f1.exists() && f1.isFile()) return f1;
else throw new IllegalArgumentException();
}

//return the largest file
return f1.length() > f2.length() ? f1 : f2 ;
}

/**
* DFS for the most extreme file, starting the search at a given directory path.
*
* @param p {@link Path} path to a directory
* @return {@link File} most extreme file in the given path
*/
static File findExtremeFile(final Path p) {

File x = null; //extreme file
final LinkedList<File> stack = new LinkedList<>(); //stack for directories
stack.push(p.toFile());
//implement dfs
while (! stack.isEmpty()){
File dir = stack.pop();
final File[] fa = dir.listFiles();
if (fa == null) {
continue; // if null then directory is probably not accessible
}

for(File f : fa){
if(f.isDirectory()) { //if directory push to stack
stack.push(f);
continue;
}
//if not directory check if extreme
if(x != null) {
x = extreme(x, f);
}
else {
x = f; //for first time
}
}
}
return x;
}
}

关于java - java中使用dfs和bfs查找计算机上最大的文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59219711/

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