gpt4 book ai didi

java - Spring Boot中如何解决 "Exception evaluating SpringEL expression"?

转载 作者:行者123 更新时间:2023-12-01 19:34:38 28 4
gpt4 key购买 nike

我在 Spring boot 应用程序中使用 Microsoft SQL。我已经弄清楚了一切,现在我正在尝试将数据从 SQL 数据库传递到前端。但是,当我通过 thymeleaf 传递信息时,它不起作用。我有一个应用程序存储库以及一个实际传递数据的 DTO 类。尽管我不断收到同样的错误。很抱歉用这么多代码轰炸大家,但我已经尝试找到解决方案一段时间了,但仍然想不出解决方法。我相信它与 TestApp 类有关,但不确定在哪里。

错误:


org.springframework.expression.spel.SpelEvaluationException: EL1008E: Property or field 'dtoTiername' cannot be found on object of type 'com.John.model.TestApp' - maybe not public or not valid?

应用程序存储库:


@Query("SELECT new com.John.model.TestApp(t.tiername, t.system) FROM AppSelectorTier t")
List<TestApp>getServerInfo();

服务层:



public List<TestApp> getServerInfo() {
List<TestApp> myList = appRepository.getServerInfo();
System.out.println(myList.size());
return myList;
}

Controller :

        @RequestMapping("/edit")
public ModelAndView editTab(Model model) {

ModelAndView modelAndView = new ModelAndView();
List<TestApp>ary4 = new ArrayList<TestApp>();
try {
System.out.println("Hello Code");
ary4 = joinQueryService.getServerInfo();
modelAndView.setViewName("create");

} catch (Exception e) {
e.printStackTrace();
modelAndView.setViewName("test");
}
modelAndView.addObject("ary4",ary4);
return modelAndView;
}

HTML:


<table class="table table-bordered table-striped">
<thead>
<tr>
<th>Tiername</th>
<th>System</th>
</tr>
</thead>

<tbody>
<tr th:each="ary4 : ${ary4}">
<td th:text="${ary4.dtoTiername}"></td>
<td th:text="${ary4.dtoSystem}"></td>
</tr>
</tbody>

</table>

测试应用:

package com.John.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

public class TestApp implements java.io.Serializable {

private String dtoTiername;
private String dtoSystem;

private static final long serialVersionUID = 1L;


//Constructor
public TestApp(String dtoTiername, String dtoSystem) {
super();
this.dtoTiername = dtoTiername;
this.dtoSystem = dtoSystem;
}

//Default Constructor
public TestApp() {

}



//Getter
public String getName() {
return dtoTiername;
}

public String getSystem() {
return dtoSystem;
}


//Setter
public void setName(String dtoTiername) {
this.dtoTiername = dtoTiername;
}


public void setSystem(String dtoSystem) {
this.dtoSystem = dtoSystem;
}

}

实体:

package com.John.model;

import java.util.*;


import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name = "tier")
public class AppSelectorTier implements java.io.Serializable {

@Id
@Column(name = "tiername")
private String tiername;

@Column(name = "system")
private String system;

private static final long serialVersionUID = 1L;


//Constructor
public AppSelectorTier(String tiername, String system) {
super();
this.tiername = tiername;
this.system = system;
}

//Default Constructor
public AppSelectorTier() {

}



//Getter
public String getName() {
return tiername;
}

public String getSystem() {
return system;
}


//Setter
public void setName(String tiername) {
this.tiername = tiername;
}


public void setSystem(String system) {
this.system = system;
}

}

最佳答案

属性由 getter 和 setter 映射,因此您可以执行其中任一操作

第一:

保持 getter setter 与变量名称对齐

public class TestApp implements java.io.Serializable  {

private String dtoTiername;
private String dtoSystem;

public String getDtoTiername() {
return dtoTiername;
}
public void setDtoTiername(String dtoTiername) {
this.dtoTiername = dtoTiername;
}
public String getDtoSystem() {
return dtoSystem;
}
public void setDtoSystem(String dtoSystem) {
this.dtoSystem = dtoSystem;
}

}

第二:

将 JSP 变量更改为

<tr th:each="ary4 : ${ary4}">
<td th:text="${ary4.name}"></td>
<td th:text="${ary4.system}"></td>
</tr>

关于java - Spring Boot中如何解决 "Exception evaluating SpringEL expression"?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59231579/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com