java - 如何正确引用此代码中的 gem 重量？

Question

如何在这段代码中引用石头的重量，以便我可以在unlockChest方法中使用它？我基本上试图将用户从对象 new Stone()) 输入的权重相加，因此它 == 组合了用户在 Chest() 构造函数中输入的值。我知道这是错误的，但我尝试了 jar1.weight，它说它不是变量。

public class Stone
{

    private String name;
    private int weight;

    public Stone()
    {
        System.out.print("Enter stone name: ");
        name = Global.keyboard.nextLine();

        System.out.print("Enter stone weight: ");
        weight = Global.keyboard.nextInt();
        Global.keyboard.nextLine();
    }
}


public class Jar
{

    private int position;
    private Stone stone;


    public Jar()
    {
        position = 0;
        stone = null;
    }

    public Jar(int initPos, Stone stone)
    {
        position = initPos;
        this.stone = stone;
    }

public class Ground
{
    private Jar jar1;
    private Jar jar2;
    private Jar jar3;
    private Player player;
    private Chest chest;

    public Ground()
    {
      player = new Player();

      jar1 = new Jar(1, new Stone());
      jar2 = new Jar(2, new Stone());
      jar3 = new Jar(3, new Stone());

      chest = new Chest()

    }

    public boolean ChestUnlocked()
    {
        if (jar1.weight + jar2.weight + jar3.weight == chest.combination) //the main problem
         return true;
        else
         return false;
    }


public class Chest
{

    public int combination;
    private int position;
    private Jar jar1;
    private Jar jar2;
    private Jar jar3;

    public Chest()
    {
        System.out.print("Enter chest combination (5-10): ");
        combination = Global.keyboard.nextInt();
        Global.keyboard.nextLine();


        position = 4;
        jar1 = new Jar(4, null);
        jar2 = new Jar(4, null);
        jar3 = new Jar(4, null);
    }

Answer 1

Stone，或许，Stone 类中的权重属性是私有(private)的。为了正确使用它们，我建议您为您的类实现 getter 方法。实现 getter 后，您可以使用如下方式调用它们:

jar1.getStone().getWeigth()

其中 getStone() 是 Jar 类中的 getter，getWeight() 是 Stone 类中的 getter。