java - JAVA程序根据出生日期和当前日期计算人的年龄

Question

此代码将从用户处接受当前日期、月份和年份；以及他们的出生日期、出生月份、出生年份。它输出人的年龄(以年、月和日为单位)。我编写的代码完成了它的工作。我已经在互联网上的一个网站上进行了交叉检查。我想知道:

How do I implement the Date class in Java to get the current Date, Month and Year? Will I be better off with Swing or AWT kits, if I want to make a GUI?

import java.util.*;
class AgeCalc
{
    static int[] MonthDays = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    public static void Input(int cd, int cm, int cy)
    {
        Scanner scan = new Scanner(System.in);
        System.out.println("Enter Birth Date");
        int bd = scan.nextShort();
        System.out.println("Enter Birth Month");
        int bm = scan.nextShort();
        System.out.println("Enter Birth Year");
        int by = scan.nextShort();
        int fnd = (DaysofMidYears(by, cy)) + Birth_CurrYearDays(bd, bm, by, cd, cm, cy);
        int y = fnd / 365;
        int m = (fnd - (y * 365)) / 30;
        int d = (fnd - (y * 365) - (m * 30));
        System.out.println("No. of Days: "+d);
        System.out.println("No. of Months: "+m);
        System.out.println("No. of Years: "+y);
    }
    public static boolean LeapYearTest(int y)
    {
        boolean lys = 
        ( ((y % 400) == 0) ? true 
        : ((y % 10) == 0) ? false 
        : ((y % 4) == 0) ? true 
        : false );
        return lys;
    }
    public static int DaysofMidYears(int by, int cy)
    {
        int dmy = 0;
        for
        (int i = (by + 1); i <= (cy - 1); i++)
        {
            dmy += 365;
            if 
            ((LeapYearTest(i)) == true)
            {
                dmy += 1;
            }
        }
        return dmy;
    }
    public static int InitialDaysofYear(int d, int m, int y)
    {
        int id = d;
        for
        (int i = 1; i <= (m - 1); i++)
        {
            id += (MonthDays[i - 1]);
        }
        if
        (((LeapYearTest(y)) == true) && (m > 2))
        {
            id += 1;
        }
        return id;
    }
    public static int Birth_CurrYearDays(int bd, int bm, int by, int cd, int cm, int cy)
    {
        int bcyd = 0;
        bcyd += (InitialDaysofYear(cd, cm, cy));
        bcyd += (365 - (InitialDaysofYear(bd, bm, by)));
        if
        ((LeapYearTest(by)) == true)
        {
            bcyd += 1;
        }
        return bcyd;
    }
}

Answer 1

我们不再使用java.util.Date或java.sql.Date类。它们在几年前就被 JSR 310 中定义的现代 java.time 类所取代。

对于没有时间和时区的仅日期值，请使用 LocalDate。

LocalDate birthDate = LocalDate.of(y, m, d);

对于耗时或年龄，请使用 Period类。

LocalDate today = LocalDate.now();
Period age = Period.between(birthDate, today);
long years = age.getYears();