ios - 根据仪器的iOS内存泄漏

Question

请帮忙!我已经阅读了内存管理规则，但是也许我想不到它们指向了某个地方。仪器告诉我以下代码存在泄漏:

NSArray *keys = [NSArray arrayWithObjects:@"text", @"score", @"subCount", nil];
NSArray *objects 
    = [NSArray arrayWithObjects:sPlateToAdd, [
         [[NSNumber alloc] initWithInt:1] autorelease], 
         [[[NSNumber alloc] initWithInt:1] autorelease], 
         nil];

NSMutableDictionary *dPlateToAdd 
    = [NSMutableDictionary dictionaryWithObjects:objects forKeys:keys];  // 93.4%        
[self.aFinals addObject:dPlateToAdd];    // 6.6%

Keys和Objects数组没有被分配或初始化，所以我不认为我需要释放那些？

然后对象中的数字被自动释放，所以可以吗？
sPlateToAdd是一个字符串，该字符串将传递到此代码所在的方法中，因此我不是该字符串的所有者，因此不需要释放它。还是我

我必须在某处做错了事。

该应用程序在iPad上运行完全正常，但在iPhone 3GS上运行缓慢，我希望修复此内存泄漏可能会加快速度...

这是创建self.aFinals的方法，该方法从文本输入中传递一个字符串。我省略了一些线条，但self.aFinals不会与它们互动

-(id)initWithTerm:(NSString *)thisTerm {
    ...
    ...
    self.aFinals = [[NSMutableArray alloc] init];

    return self;
}

然后，我有大约5个嵌套循环，在所有循环中间调用了3次addPlateToFinals，创建了 thisPlate ，它变成了 sPlateToAdd

// replace 1st occurance
NSString *thisPlate = [thisBase
    stringByReplacingOccurrencesOfRegex:[NSString stringWithFormat:
        @"(^[^%@]+)%@(.*$)", 
        thisChar, 
        thisChar] 
     withString:[NSString stringWithFormat:@"$1%@$2", thisSub]
     ];

     [self addPlateToFinals:thisPlate withSubCount:thisSubCount];
 // replace 2nd occurance
 thisPlate = [thisBase
     stringByReplacingOccurrencesOfRegex:[NSString stringWithFormat:
         @"(^[^%@]+%@.*)%@",    
         thisChar, 
         thisChar, 
         thisChar] 
     withString:[NSString stringWithFormat:@"$1", thisSub]
     ];

 // then it does it again, with slightly different regex

这是泄漏来自的完整方法:

-(void)addPlateToFinals:(NSString *)sPlateToAdd withSubCount:(NSNumber *)nSubCount {
// plate must be less than 7 characters and great than 2 chars
if (
    [sPlateToAdd length] <= [self.nPlateMax intValue] &&
    [sPlateToAdd length] >= [self.nPlateMin intValue]
    ) {    

    NSMutableArray *aSearchFinals = [self arrayOfFinals];

    // add plate if it is not already in the finals array   
    if(![aSearchFinals containsObject:sPlateToAdd]) {

        // filter out results that cannot be converted to valid plates
        NSPredicate *potential = [NSPredicate predicateWithFormat: @"SELF MATCHES '^[a-z]{0,3}[0-9]{1,3}[a-z]{0,3}$'"];
        NSPredicate *impossible1 = [NSPredicate predicateWithFormat: @"SELF MATCHES '^[a-z]{2}[0-9]{2,3}[a-z]{2}$'"];
        NSPredicate *impossible2 = [NSPredicate predicateWithFormat: @"SELF MATCHES '^[a-z][0-9]{3}$'"];
        NSPredicate *impossible3 = [NSPredicate predicateWithFormat: @"SELF MATCHES '^[a-z]{2}[0-9]{2}$'"];
        NSPredicate *impossible4 = [NSPredicate predicateWithFormat: @"SELF MATCHES '^[0-9]{2}[a-z]{2}$'"];

        if(
            [potential evaluateWithObject: sPlateToAdd] && 
            ![impossible1 evaluateWithObject: sPlateToAdd] &&
            ![impossible2 evaluateWithObject: sPlateToAdd] &&
            ![impossible3 evaluateWithObject: sPlateToAdd] &&
            ![impossible4 evaluateWithObject: sPlateToAdd]
        ){                  

            NSArray *keys = [NSArray arrayWithObjects:@"text", @"score", @"subCount", nil];
            NSArray *objects = [NSArray arrayWithObjects:
                                    sPlateToAdd, 
                                    [[[NSNumber alloc] initWithInt:1] autorelease], 
                                    [[[NSNumber alloc] initWithInt:1] autorelease], 
                                    nil
                                ];

            NSDictionary *dPlateToAdd = [NSDictionary dictionaryWithObjects:objects forKeys:keys];          
            [self.aFinals addObject:dPlateToAdd];   
        }
    }
}

}

Answer 1

您应该显示整个`addPlateToFinals'方法，sPlateToAdd可能会泄漏。

基于新添加的代码，如果使用keep声明属性，则self.aFinals泄漏(我是％99)。应该:
self.aFinals = [[[NSMutableArray alloc] init] autorelease]
甚至更好:
self.aFinals = [NSMutableArray array]