java - 如何使用mockito抛出JsonProcessingException

Question

我的代码中有以下几行:

@Autowired
private ObjectMapper mapper = new ObjectMapper();

@PostMapping("/postPrueba")
public ResponseEntity<String> postPrueba(@RequestBody Prueba prueba) {

    String pTest = null;
    try {
        pTest  = mapper.writeValueAsString(prueba);
        System.out.println(pTest  );
    } catch (JsonProcessingException e) {
        return new ResponseEntity<>("", HttpStatus.INTERNAL_SERVER_ERROR);
    }
        return new ResponseEntity<>("", HttpStatus.OK);
}

我的模型Prueba.java

public class Prueba {

    @Id
    private String nombre;
    private String apellidos;
    private String edad;
}

在测试中我想强制 JsonProcessingException 但我不能。我已经尝试过这个:

@Mock
private ObjectMapper mapperMock;

@Test
public void testKo() throws Exception {

    ObjectMapper om = Mockito.spy(new ObjectMapper());
    Mockito.when(this.mapperMock.writeValueAsString(Mockito.any())).thenThrow(new JsonProcessingException("") {});

    ObjectMapper om = Mockito.spy(new ObjectMapper());
    Mockito.when( om.writeValueAsString(Mockito.eq(Prueba.class))).thenThrow(new JsonProcessingException("") {});

    Mockito.when(this.mapperMock.writeValueAsString(Mockito.eq(Prueba.class))).thenThrow(new JsonProcessingException("") {});

    String jsonContent = "{'nombre': '123456', 'apellidos': '12'}";
    jsonContent = jsonContent.replaceAll("\'", "\"");

    this.mvc.perform(post("/postPrueba")
                .contentType(MediaType.APPLICATION_JSON)
                .content(jsonContent))
                .andExpect(status().is5xxServerError());
    }

但响应始终是 200 OK。我该怎么做？

Answer 1

  doThrow(JsonProcessingException.class).when(object).method(...);