iphone - 如何从远程推送通知中获取我的应用程序中的notification.alertBody？

Question

我刚刚按照本教程Push notification进行操作，并成功为我的iPhone应用程序实现了推送通知。我现在可以获取通知详细信息。但是，我想将通知alertBody放在为通知alertBody提供的标签上。

我在显示本地通知中的通知alertBody时有一个代码。但我知道它与推送通知不同，因为它仅用于本地通知。

在我的AppDelagate.m上

- (void)application:(UIApplication *)app didReceiveLocalNotification:(UILocalNotification *)notif {
NSLog(@"Recieved Notification %@",notif);
NSString *_stringFromNotification = notif.alertBody;
[[NSNotificationCenter defaultCenter] postNotificationName:@"Notification" object:_stringFromNotification];
}

在我的ViewController.m上

- (void)viewDidLoad{

 [super viewDidLoad];     

[[NSNotificationCenter defaultCenter] addObserverForName:@"Notification" object:nil queue:nil usingBlock:^(NSNotification *note)
NSString *_string = note.object;
//Do something with the string--------
}];

}

它在“本地通知”上完美运行，但对于推送通知，则不起作用。如何实现呢？请需要您的帮助。我需要将通知警报正文放在“标签”或“字符串”处。

Answer 1

first of all register for remote notifications in AppDelegate.m in method,

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
//Invoke APNS.
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     (UIRemoteNotificationTypeBadge | UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];
}

And then use following delegate method to recieve remote notification:
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
    NSLog(@"Received =%@",userInfo);////userInfo will contain all the details of notification like alert body.
}