Java:抓取数字

Question

我创建了一个java电话簿(桌面应用程序)，在我的电脑上有一个程序可以输出调用者的号码。这是一个 8 位数字。

这是它的工作原理

我只想从弹出窗口中抓取 8 位数字，所以假设这是一个弹出窗口:

    My name is someone like you, i am 22 years old, i was born in 19/10/1989,
    my phone number is 34544512
    my brother is someone like me he is 18 years old, born in 9101993 
    his number is 07777666

在此示例中，我只想抓取 07777666 和 34544512。

我想每2秒检查一次弹出窗口是否有新号码，如果调用者给我打电话两次，他的号码将已经存储在我的数据库中，如果没有，我将存储

注意:如果这做不到，那就忘记弹出窗口，假设它只是每 2 秒更新一次的文本，如何抓取它

这不是作业哈哈:D

Answer 1

使用Java正则表达式。创建 8 位或更多数字的正则表达式并使用它。您将能够从文本样本中提取这 2 个电话号码。

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
    public static void main(String args[]) throws Exception {
        String testString = "My name is someone like you, i am 22 years old, i was born in 19/10/1989,"
                          + " my phone number is  34544512 3454451266"
                          + " my brother is someone like me he is 18 years old, born in 9101993 "
                          + " his number is 07777666";

        String[] pieces = testString.split("\\s+");
        String expression = "\\d{8,}";
        Pattern pattern = Pattern.compile(expression);
        for (int i = 0; i < pieces.length; i++) {
            if (pattern.matches(expression, pieces[i]))
                System.out.println(pieces[i]);
        }
    }
}