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Java - 调用嵌套类中的方法,特别是 ActionListener

转载 作者:行者123 更新时间:2023-12-01 19:07:34 24 4
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编辑:已解决,添加组件后我没有使用“validate()”。

我有一个 GUI 类,其结构如下(这是我的代码的非常基本的表示):

编辑:这是我的完整代码

package source;

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.event.*;

public class Gui extends JFrame
{
public String[] list1 = {"equation1","equation2","equation3","equation4", "equation5"};
public JOptionPane opt1;
private JButton custom;
private JTextField[] tf;
public HandlerClass2 itemhandler = new HandlerClass2();
private JList list;
private static int index = 0;
private static int lastlistindex = 0;
private JPanel buttonpanel;
private JPanel buttonpanel2[] = new JPanel[3];
private JPanel listpanel[] = new JPanel[4];
private JPanel checkpanel;
private JCheckBox checkboxes[];
private SpringLayout layout;
public Container contentPane;
private JButton but;

public Gui()
{
super("Physics Helper v0.1");
setBackground(Color.DARK_GRAY);

layout = new SpringLayout();

contentPane = getContentPane();
contentPane.setLayout(layout);

displayPortal();
}

public void displayPortal()
{
Icon a = new ImageIcon(getClass().getResource("button.png"));
Icon b = new ImageIcon(getClass().getResource("button2.png"));
custom = new JButton("", a);
custom.setRolloverIcon(b);

buttonpanel = new JPanel();
buttonpanel.setBackground(Color.GRAY);
buttonpanel.add(custom);
contentPane.add(buttonpanel);

layout.putConstraint(SpringLayout.WEST, buttonpanel, 5, SpringLayout.WEST, contentPane);
layout.putConstraint(SpringLayout.EAST, buttonpanel, -5, SpringLayout.EAST, contentPane);
layout.putConstraint(SpringLayout.NORTH, buttonpanel, 5, SpringLayout.NORTH, contentPane);

custom.addActionListener(new HandlerClass());

}

public void displayButton(String s)
{
but = new JButton(s);

buttonpanel2[index] = new JPanel();
buttonpanel2[index].setBackground(Color.GRAY);
buttonpanel2[index].add(but);

contentPane.add(buttonpanel2[index]);

layout.putConstraint(SpringLayout.SOUTH, buttonpanel2[index], -5, SpringLayout.SOUTH, contentPane);

if (index < 1)
{
layout.putConstraint(SpringLayout.WEST, buttonpanel2[index], 5, SpringLayout.WEST, contentPane);
}
else
{
layout.putConstraint(SpringLayout.WEST, buttonpanel2[index], 5, SpringLayout.EAST, buttonpanel2[index - 1]);
}

index++;
}

public void displayList(String[] t)
{
list = new JList(t);
list.setVisibleRowCount(8);
list.setSelectionMode(ListSelectionModel.SINGLE_SELECTION);
add(new JScrollPane(list));

listpanel[lastlistindex] = new JPanel();
listpanel[lastlistindex].setBackground(Color.GRAY);
listpanel[lastlistindex].add(list);

contentPane.add(listpanel[lastlistindex]);

layout.putConstraint(SpringLayout.NORTH, listpanel[lastlistindex], 5, SpringLayout.SOUTH, buttonpanel);

if (lastlistindex < 1)
{
layout.putConstraint(SpringLayout.WEST, listpanel[lastlistindex], 5, SpringLayout.WEST, contentPane);
}
else
{
layout.putConstraint(SpringLayout.WEST, listpanel[lastlistindex], 5, SpringLayout.EAST, listpanel[lastlistindex - 1]);
}

lastlistindex++;
}

public void displayInputValues(String[] p)
{
checkboxes = new JCheckBox[p.length];

GridLayout gridlayout = new GridLayout(p.length, 2);
tf = new JTextField[p.length];

checkpanel = new JPanel();
checkpanel.setBackground(Color.GRAY);
checkpanel.setLayout(gridlayout);

for (int b = 0; b < p.length; b++)
{
checkboxes[b] = new JCheckBox(p[b]);
checkpanel.add(checkboxes[b]);

tf[b] = new JTextField("", 9);
checkpanel.add(tf[b]);
tf[b].setFont(new Font("Serif", Font.PLAIN, 14));
}

contentPane.add(checkpanel);

layout.putConstraint(SpringLayout.EAST, checkpanel, -5, SpringLayout.EAST, contentPane);
layout.putConstraint(SpringLayout.SOUTH, checkpanel, -5, SpringLayout.SOUTH, contentPane);
}

private class HandlerClass implements ActionListener
{

public void actionPerformed(ActionEvent event)
{
displayButton("Back");
displayButton("Next");

displayList(list1);
}
}

我的主要方法包含在另一个类中,并且工作正常。

我的问题是如何在actionPerformed方法中调用“displayButton”方法?我已经尝试了一些技巧,例如使用“Gui.this.displayButton("Press me!") 来调用它。

我已经测试了代码的所有其他方面,这似乎是唯一的问题。

运行代码时没有出现错误。

如果需要,我可以发布完整的类(class),但我认为这个问题在于尝试调用这些方法。

你有什么看法?

最佳答案

调用该方法工作正常,不需要任何花哨的东西

您需要将 HandlerClass 的实例添加到 GUI 控件,例如 JButton,单击该控件时将触发该方法。这就是 ActionListeners(以及一般的监听器)的全部要点。例如:

myJButton.addActionListener(new HandlerClass());

基于您的代码的工作示例:

public class Gui extends JFrame
{
public Gui()
{
super("Physics Helper v0.1");
JButton b = new JButton("Press me!");
b.addActionListener(new HandlerClass());
add(b);
pack();
setVisible(true);
}

public void displayButton(String s)
{
System.out.println(s);
}

private class HandlerClass implements ActionListener
{
public void actionPerformed(ActionEvent event)
{
displayButton("Press me!");
}
}

public static void main(String[] args)
{
new Gui();
}
}

关于Java - 调用嵌套类中的方法,特别是 ActionListener,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9502880/

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