java - 将 c++ 代码转换为 java 代码时出现 java.lang.StringIndexOutOfBoundsException

Question

我正在努力解决这个问题

https://vjudge.net/problem/UVALive-6805

我找到了解决方案，但是在 C++ 中，任何人都可以帮我将其转换为 java 代码。我是编程新手

我尝试了很多解决方案，但没有一个有效。

如果可能的话，我需要帮助

我不知道 Java 中 C++ 中的 .erase 函数的等价物是什么C++ 中的 sbstr 是否提供与 java 不同的结果？

#include <iostream>
#include <string>

    using namespace std;

    int syllable(string word)
    {
        int L = word.size();
        int syllable;

        if (L>=7)
        {
            syllable = 3;
        }
        else if (L==6)
        {
            int indicator = 0;

            for (int k=0; k<=L-2; k++)
            {
                string subword = word.substr(k, 2);
                if (subword == "ng" || subword == "ny")
                {
                    indicator++;
                }
            }

            if (indicator == 0)
            {
                syllable = 3;
            }
            else
            {
                syllable = 2;
            }
        }
        else if (L == 4 || L == 5)
        {
            syllable = 2;
        }
        else if (L == 3)
        {
            char Char = word[0];

            if (Char=='a' || Char=='A' || Char=='e' || Char=='E' || Char=='i' || Char=='I' || Char=='o' || Char=='O' || Char=='u' || Char=='U')
            {
                syllable = 2;
            }
            else
            {
                syllable = 1;
            }
        }
        else
        {
            syllable = 1;
        }

        return syllable;
    }

    int main()
    {
        string word;

        int T;

        cin >> T;

        for (int i=1; i<=T; i++)
        {

            int syl[] = {0, -1, -2, -3};
            string rhy[] = {"a", "b", "c", "d"};

            int verse = 0;

            int stop = 0;

            while (stop == 0)
            {
                cin >> word;

                int L = word.size();

                char end = word[L-1];

                if (end == '.')
                {
                    stop = 1;
                }

                if (word[L-1] == ',' || word[L-1] == '.')
                {
                    word = word.erase(L-1, 1);
                    L = word.size();
                }

                if (verse<=3)
                {
                    syl[verse] = syl[verse] + syllable(word);
                }

                if (end == ',' || end == '.')
                {
                    if (verse<=3)
                    {
                        rhy[verse] = word.substr(L-2, 2);
                    }

                    verse++;

                    if (verse<=3)
                    {
                        syl[verse] = 0;
                    }
                }
            }

            int A = 0, B = 0, C = 0, D = 0;

            for (int k=0; k<4; k++)
            {
                if (syl[k] >= 8 && syl[k] <= 12)
                {
                    A = A + 10;
                }
            }

            for (int k=0; k<2; k++)
            {
                if (rhy[k] == rhy[k+2])
                {
                    B = B + 20;
                }
            }

            for (int k=0; k<2; k++)
            {
                if (syl[k] == syl[k+2])
                {
                    C = C + 10;
                }
            }

            if (verse > 4)
            {
                D = (verse - 4) * 10;
            }

            int E = A + B + C - D;

            cout << "Case #" << i << ": " << A << " " << B << " " << C << " " << D << " " << E << endl;         
        }
    }

这是我的尝试

import java.util.*;

public class First {

    public static int syllable(String word) {
        int L = word.length();
        int syllable;

        if (L >= 7) {
            syllable = 3;
        } else if (L == 6) {
            int indicator = 0;

            for (int k = 0; k < L - 3; k++) {
                String subword = word.substring(k, 2);
                if (subword == "ng" || subword == "ny") {
                    indicator++;
                }
            }

            if (indicator == 0) {
                syllable = 3;
            } else {
                syllable = 2;
            }
        } else if (L == 4 || L == 5) {
            syllable = 2;
        } else if (L == 3) {
            char Char = word.charAt(0);

            if (Char == 'a' || Char == 'A' || Char == 'e' || Char == 'E' || Char == 'i' || Char == 'I' || Char == 'o'
                    || Char == 'O' || Char == 'u' || Char == 'U') {
                syllable = 2;
            } else {
                syllable = 1;
            }
        } else {
            syllable = 1;
        }

        return syllable;
    }

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        String word;

        int T;

        T = sc.nextInt();

        for (int i = 1; i <= T; i++) {

            int syl[] = { 0, -1, -2, -3 };
            String rhy[] = { "a", "b", "c", "d" };

            int verse = 0;

            int stop = 0;

            while (stop == 0) {

                word = sc.next();

                int L = word.length();

                char end = word.charAt(L-1);

                if (end == '.') {
                    stop = 1;
                }

                if (word.charAt(L-1) == ',' || word.charAt(L-1) == '.') {

                    word.substring(L-1, 1);
                    L = word.length();
                }

                if (verse <= 3) {
                    syl[verse] = syl[verse] + syllable(word);
                }

                if (end == ',' || end == '.') {
                    if (verse <= 3) {

                        rhy[verse] = word.substring(L - 2, 2);
                    }

                    verse++;

                    if (verse <= 3) {
                        syl[verse] = 0;
                    }
                }
            }

            int A = 0, B = 0, C = 0, D = 0;

            for (int k = 0; k < 4; k++) {
                if (syl[k] >= 8 && syl[k] <= 12) {
                    A = A + 10;
                }
            }

            for (int k = 0; k < 2; k++) {
                if (rhy[k] == rhy[k + 2]) {
                    B = B + 20;
                }
            }

            for (int k = 0; k < 2; k++) {
                if (syl[k] == syl[k + 2]) {
                    C = C + 10;
                }
            }

            if (verse > 4) {
                D = (verse - 4) * 10;
            }

            int E = A + B + C - D;

            System.out.println("Case #" + i + ": " + A + " " + B + " " + C + " " + D + " " + E);
        }
    }

}

Answer 1

第二次和第三次调用 String 子字符串方法时抛出异常。您的 beginIndex 高于您的 endIndex。正如您在这里看到的 https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring(int,%20int) beginIndex 始终必须低于 endIndex。