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java - 使用java套接字进行文件传输: Error on client side "Exception in thread "main"java. lang.NullPointerException”

转载 作者:行者123 更新时间:2023-12-01 19:01:43 25 4
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指导我解决这个异常。我一直在尝试将文件从客户端发送到服务器 - 在客户端中手动输入文件名。但我在客户端收到 NullPointerException - 据我所知,可能的错误是“在打开文件之前,我传递了一个 null 参数,因此是 NPE”

服务器.java

import java.io.FileOutputStream;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.net.ServerSocket;
import java.net.Socket;

public class Server extends Thread {
public static final int PORT = 3333;
public static final int BUFFER_SIZE = 100;

@Override
public void run() {
try {
ServerSocket serverSocket = new ServerSocket(PORT);

while (true) {
Socket s = serverSocket.accept();
saveFile(s);
}
} catch (Exception e) {
e.printStackTrace();
}
}

private void saveFile(Socket socket) throws Exception {
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
FileOutputStream fos = null;
byte [] buffer = new byte[BUFFER_SIZE];

// 1. Read file name.
Object o = ois.readObject();

if (o instanceof String) {
fos = new FileOutputStream(o.toString());
} else {
throwException("Something is wrong");
}

// 2. Read file to the end.
Integer bytesRead = 0;

do {
o = ois.readObject();

if (!(o instanceof Integer)) {
throwException("Something is wrong");
}

bytesRead = (Integer)o;

o = ois.readObject();

if (!(o instanceof byte[])) {
throwException("Something is wrong");
}

buffer = (byte[])o;

// 3. Write data to output file.
fos.write(buffer, 0, bytesRead);
} while (bytesRead == BUFFER_SIZE);

fos.close();

ois.close();
oos.close();
}

public static void throwException(String message) throws Exception {
throw new Exception(message);
}

public static void main(String[] args) {
new Server().start();
}
}

客户端.java

import java.io.File;
import java.io.FileInputStream;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.net.Socket;
import java.util.Arrays;
import java.lang.*;

public class Client {
public static void main(String[] args) throws Exception {
String fileName = null;

try {
fileName = args[0];
} catch (Exception e) {
System.out.println("Enter the name of the file :");
}
File file = new File(fileName);
Socket socket = new Socket("localhost", 3333);
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());

oos.writeObject(file.getName());

FileInputStream fis = new FileInputStream(file);
byte [] buffer = new byte[Server.BUFFER_SIZE];
Integer bytesRead = 0;

while ((bytesRead = fis.read(buffer)) > 0) {
oos.writeObject(bytesRead);
oos.writeObject(Arrays.copyOf(buffer, buffer.length));
}

oos.close();
ois.close();
}
}

最佳答案

String fileName = null;

try {
fileName = args[0];
} catch (Exception e) {
System.out.println("Enter the name of the file :");
}
File file = new File(fileName);

上面的代码只是检查用户是否提供了文件名。即使用户没有输入任何文件名,它也会继续进行,结果 null 作为参数传递给 File 构造函数。因此你的NPE

File 实例化也放入 try catch block 中。其次,File 构造函数将文件的整个路径作为参数,因此请确保您正在使用的文件位于当前工作目录中。

关于java - 使用java套接字进行文件传输: Error on client side "Exception in thread "main"java. lang.NullPointerException”,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12035556/

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