ios - 即使在 ios 中滚动后也将 UIPickerView 的位置设置在底部

Question

我正在尝试显示 UIPickerView点击UITextField .我用一个简单的方法来显示picker如下:

-(void) showPickerView {

    [self.view resignFirstResponder];
    [UIView beginAnimations:nil context:nil];
    [UIView setAnimationDuration:0.50];
    [UIView setAnimationCurve:UIViewAnimationCurveEaseOut];

    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
    if(iOSDeviceScreenSize.height == 480){

        CGRect frame = self.picker.frame;
        frame.origin.y = 270;
        self.picker.frame = frame;
        frame = self.toolBar.frame;
        frame.origin.y = 226.0;
        self.toolBar.frame = frame;

    } else if(iOSDeviceScreenSize.height == 568){

        CGRect frame = self.picker.frame;
        frame.origin.y = 239.0;
        self.picker.frame = frame;
        frame = self.toolBar.frame;
        frame.origin.y = 195.0;
        self.toolBar.frame = frame;

    }

    [UIView commitAnimations];

}

如果我没有向下滚动，它会很好用。但是当我向下滚动时，我的 picker放置在 showPickerView 中提到的固定位置方法。现在我该如何管理我的 picker每次都出现在底部。

Answer 1

解决方案一:

将您的选择器 View 添加到您的窗口。

方案二:

实现 ScrollView 委托(delegate)并不断调整框架。

- (void)scrollViewDidScroll:(UIScrollView *)scrollView
{


    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;
    if(iOSDeviceScreenSize.height == 480){

        CGRect frame = self.picker.frame;
        frame.origin.y = 270;
        self.picker.frame = frame;
        frame = self.toolBar.frame;
        frame.origin.y = 226.0;
        self.toolBar.frame = frame;

    } else if(iOSDeviceScreenSize.height == 568){

        CGRect frame = self.picker.frame;
        frame.origin.y = 239.0;
        self.picker.frame = frame;
        frame = self.toolBar.frame;
        frame.origin.y = 195.0;
        self.toolBar.frame = frame;

    }



}