gpt4 book ai didi

r - `dplyr::full_join()` 不适用于列表列

转载 作者:行者123 更新时间:2023-12-01 18:58:24 25 4
gpt4 key购买 nike

我正在尝试比较 R 包中给定函数的两个版本的形式 ggstatsplot 。我已经能够在 tibbles 中提取形式,但我似乎无法将这两个表连接起来。 dplyr::full_join()产生一个错误,但并不清楚它会带来什么。如果有任何关于如何加入这两个数据框的反馈,我将不胜感激。

# setup
set.seed(123)
library(tidyverse)
library(ggstatsplot)

# formals for the primary version of the function
(df_primary <- tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
dplyr::rename(.data = ., primary = value))
#> # A tibble: 41 x 2
#> name primary
#> <chr> <list>
#> 1 data <NULL>
#> 2 x <missing>
#> 3 binwidth <NULL>
#> 4 bar.measure <chr [1]>
#> 5 xlab <NULL>
#> 6 title <NULL>
#> 7 subtitle <NULL>
#> 8 caption <NULL>
#> 9 type <chr [1]>
#> 10 test.value <dbl [1]>
#> # ... with 31 more rows

# formals for the grouped version of the function
(df_grouped <- tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
dplyr::rename(.data = ., grouped = value))
#> # A tibble: 43 x 2
#> name grouped
#> <chr> <list>
#> 1 data <missing>
#> 2 x <missing>
#> 3 grouping.var <missing>
#> 4 title.prefix <NULL>
#> 5 binwidth <NULL>
#> 6 bar.measure <chr [1]>
#> 7 xlab <NULL>
#> 8 subtitle <NULL>
#> 9 caption <NULL>
#> 10 type <chr [1]>
#> # ... with 33 more rows

# joining the two dataframes name
dplyr::full_join(
x = df_primary,
y = df_grouped,
by = "name"
)
#> Error: type not supported

traceback()
#> 4: stop(list(message = "type not supported", call = NULL, cppstack = NULL))
#> 3: full_join_impl(x, y, by_x, by_y, aux_x, aux_y, na_matches, environment())
#> 2: full_join.tbl_df(x = tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
#> dplyr::rename(.data = ., primary = value), y = tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
#> dplyr::rename(.data = ., grouped = value), by = "name")
#> 1: dplyr::full_join(x = tibble::enframe(formals(ggstatsplot::gghistostats)) %>%
#> dplyr::rename(.data = ., primary = value), y = tibble::enframe(formals(ggstatsplot::grouped_gghistostats)) %>%
#> dplyr::rename(.data = ., grouped = value), by = "name")

reprex package 于 2019-01-25 创建(v0.2.1)

最佳答案

似乎不支持点配对类型。一件事,我们可以将其转换为普通的 list,然后执行 full_join

formals(ggstatsplot::gghistostats) %>% 
as.list %>%
tibble::enframe(value = 'primary') %>%
full_join(formals(ggstatsplot::grouped_gghistostats) %>%
as.list %>%
tibble::enframe(value = 'grouped'))
# A tibble: 40 x 3
# name primary grouped
# <chr> <list> <list>
# 1 data <NULL> <missing>
# 2 x <missing> <missing>
# 3 binwidth <NULL> <NULL>
# 4 bar.measure <chr [1]> <chr [1]>
# 5 xlab <NULL> <NULL>
# 6 title <NULL> <NULL>
# 7 subtitle <NULL> <NULL>
# 8 caption <NULL> <NULL>
# 9 type <chr [1]> <chr [1]>
#10 test.value <dbl [1]> <dbl [1]>
# … with 30 more rows

关于r - `dplyr::full_join()` 不适用于列表列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54367104/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com