java - 数组不会通过 for 循环到达下一个位置

Question

这是我的代码:

ArrayFunHouseTwo

public class ArrayFunHouseTwo
{
//goingUp() will return true if all numbers
//in numArray are in increasing order
//[1,2,6,9,23] returns true
//[9, 11, 13, 8]  returns false
public static boolean goingUp(int[] numArray)
{
    int num = 0;
    int numMinus = 0;
    for(int x = 1; x < numArray.length; x++){
        System.out.println(x);
        num = numArray[x];
        numMinus = numArray[x-1];

        if(num > numMinus){
            return true;
        }

    }
    return false;           
}

以及关联的运行器类:

import java.util.Arrays;

public class Lab14b
{
public static void main( String args[] )
{
    int[] one = {1,2,3,4,5,6,7,8,9,10};
    int[] two = {1,2,3,9,11,20,30};
    //add more test cases
    //int[] three = {9,8,7,6,5,4,3,2,0,-2};
    //int[] four = {3,6,9,12,15,18,21,23,19,17,15,13,11,10,9,6,3,2,1,0};

    System.out.println(Arrays.toString(one));
    System.out.println("is going Up ?  " + ArrayFunHouseTwo.goingUp(one));
    System.out.println(Arrays.toString(two));
    System.out.println("is going Up ?  " + ArrayFunHouseTwo.goingUp(two));
    //add more test cases
    //System.out.println(Arrays.toString(three));
    //System.out.println("is going Up ?  " + ArrayFunHouseTwo.goingUp(three));
    //System.out.println(Arrays.toString(four));
    //System.out.println("is going Up ?  " + ArrayFunHouseTwo.goingUp(four));

我希望它打印出来，从而证明它正在读取整个数组，但它读取的唯一数组是第三个数组，它将打印位置 x 处的所有值或 x 的值，取决于我如何编写 println() 语句

Answer 1

if(num > numMinus){
    return true;
}

这意味着一旦发现一个数字大于之前的数字，就会终止循环。此时您想要做的事情是这样的。

...
    if(num <= numMinus){
        return false;
    }
}
return true;
}

编辑:将条件修复为 <=基本上，您检查连续的数字，如果数字相等或递减，则将标志设置为 false(实际上此时您可以返回 false)