java - ListView 中的可点击项目

Question

我正在尝试使我的 ListView 项目可点击；但无法让它正常工作。当我单击某个项目时，它会切换屏幕，但不会切换到所需的屏幕。这是代码

private ListView lv;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_signup);
    lv = (ListView) findViewById(R.id.listView1);
    // Instanciating an array list (you don't need to do this, you already have yours)
    ArrayList<String> menu_Items = new ArrayList<String>();
    menu_Items.add("Fill Treatment Form");
    menu_Items.add("View Medical History");
    menu_Items.add("View Medication");
    menu_Items.add("View Diet");
    menu_Items.add("View First Aid");
    menu_Items.add("Look Up Map");
    menu_Items.add("Account Settings");
    // This is the array adapter, it takes the context of the activity as a first // parameter, the type of list view as a second parameter and your array as a third parameter
    ArrayAdapter<String> arrayAdapter =      
    new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1, menu_Items);
    lv.setAdapter(arrayAdapter);


    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg0, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(), FillTreatmentActivity.class);
            startActivity(i);

        }

    });

    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg1, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(), MedicalHistoryActivity.class);
            startActivity(i);
        }
    });

    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg2, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(), MedicationActivity.class);
            startActivity(i);
        }
    });

    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg3, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(),DietActivity.class);
            startActivity(i);
        }
    });

    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg4, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(),FirstAidActivity.class);
            startActivity(i);
        }
    });

    lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg5, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(),MapActivity.class);
            startActivity(i);
        }
    });

   lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> arg6, View view, int position, long id) {

            Intent i = new Intent(getApplicationContext(),SettingsActivity.class);
            startActivity(i);
        }
    }); 
}

当我单击任何 ListView 项目时，帐户设置 Activity 将打开。我是新手，所以请不要评判我的编码:)

Answer 1

ListView 只能有一个 OnItemClickListener，因此除了最后一个之外的所有内容都会被丢弃。这就是为什么无论您点击哪个项目，SettingsActivity 都是开放的。

要解决这个问题，请使用一个监听器并让该监听器处理不同的选项。

lv.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> arg1, View view, int position, long id) {
        switch(position) {
           case 0:
               // start activity 1
               break;
           case 1:
               // start activity 2
               break;
           case 2:
               // start activity 3
               break;
           // more case statements

    }
});