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java - 转换时出现异常 "JSONArray cannot be converted to JSONObject error"

转载 作者:行者123 更新时间:2023-12-01 18:50:08 27 4
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我有 JSON 响应

           {"as_of":"2013-04-22T19:50:41Z","trends":[{"events":null,
"query":"%23RhymeATweepsName","url":"http:\/\/twitter.com\/search?
q=%23RhymeATweepsName","promoted_content":null,
"name":"#RhymeATweepsName"},
{"events":null,"query":"%23EarthDayPK","url":
"http:\/\/twitter.com\/search?
=%23EarthDayPK","promoted_content":null,"name":
"#EarthDayPK"}],"locations":
[{"woeid":*******,"name":"********"}],"created_at":"2013-04-22T19:38:16Z"}

我正在使用以下代码解析它

             jArray = new JSONArray(result);
JSONObject post = null;
for (int ii = 0; ii < jArray.length(); ii++) {
post = jArray.getJSONObject(ii);
String name = post.getJSONObject("trends").getString("name") + "\n";
}
}

但它抛出异常“JSONArray无法转换为JSONObject错误”

最佳答案

如 JSON 中所示,trends 不是 JSONObject,而是 JSONArray:

"trends":[
{
"events":null,
"query":"%23RhymeATweepsName",
"url":"http:\/\/twitter.com\/search? q=%23RhymeATweepsName",
"promoted_content":null,
"name":"#RhymeATweepsName"
},
{
"events":null,
"query":"%23EarthDayPK",
"url":"http:\/\/twitter.com\/search? =%23EarthDayPK",
"promoted_content":null,
"name":"#EarthDayPK"
}
]

你应该像这样解析它:

String name = post.getJSONArray("trends").getJSONObject(0).getString("name");
// or iterate... ^^

关于java - 转换时出现异常 "JSONArray cannot be converted to JSONObject error",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16155578/

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