ios - 与ABAddressBook重复联系

Question

我正在使用ABAddressBook，可以显示每个联系人，但是我有一些重复的联系人。

我已经阅读了这个主题:Dealing with duplicate contacts due to linked cards in iOS' Address Book API，但是无法解决问题。

我想在我的代码中使用此代码，但我没有成功..:

NSMutableSet *unifiedRecordsSet = [NSMutableSet set];

ABAddressBookRef addressBook = ABAddressBookCreate();
CFArrayRef records = ABAddressBookCopyArrayOfAllPeople(addressBook);
for (CFIndex i = 0; i < CFArrayGetCount(records); i++)
{
    NSMutableSet *contactSet = [NSMutableSet set];

    ABRecordRef record = CFArrayGetValueAtIndex(records, i);
    [contactSet addObject:(__bridge id)record];

    NSArray *linkedRecordsArray = (__bridge NSArray *)ABPersonCopyArrayOfAllLinkedPeople(record);
    [contactSet addObjectsFromArray:linkedRecordsArray];

    // Your own custom "unified record" class (or just an NSSet!)
    DAUnifiedRecord *unifiedRecord = [[DAUnifiedRecord alloc] initWithRecords:contactSet];

    [unifiedRecordsSet addObject:unifiedRecord];
    CFRelease(record);
}

CFRelease(records);
CFRelease(addressBook);

_unifiedRecords = [unifiedRecordsSet allObjects];

这是我的代码:

- (void)getPersonOutOfAddressBook
{
    //1
    CFErrorRef error = NULL;
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);

    if (addressBook != nil) {
        NSLog(@"Succesful.");

        //2
        NSArray *allContacts = (__bridge_transfer NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);


        //3
        NSUInteger i = 0; for (i = 0; i < [allContacts count]; i++)
        {
            Person *person = [[Person alloc] init];
            ABRecordRef contactPerson = (__bridge ABRecordRef)allContacts[i];

            //4
            NSString *firstName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson,
                                                                                  kABPersonFirstNameProperty);
            if (firstName == nil)
            {
                firstName = @"";
            }
            NSString *lastName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonLastNameProperty);
            if (lastName == nil)
            {
                lastName = @"";
            }
            NSString *fullName = [NSString stringWithFormat:@"%@ %@", firstName, lastName];

            person.firstName = firstName; person.lastName = lastName;
            person.fullName = fullName;



            //phone
            //5
            ABMultiValueRef phones = ABRecordCopyValue(contactPerson, kABPersonPhoneProperty);

            //6
            NSUInteger j = 0;
            for (j = 0; j < ABMultiValueGetCount(phones); j++) {
                NSString *phone = (__bridge_transfer NSString *)ABMultiValueCopyValueAtIndex(phones, j);

                if (j == 0) {
                    person.mainNumber = phone;
                }
                else if (j==1) person.secondNumber = phone;
            }

            //7
            [person.mainNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
            [person.mainNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
            [person.mainNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
            [person.mainNumber stringByReplacingOccurrencesOfString:@"+336" withString:@"06"];
            [self.tableData addObject:person];
            [self.contact addObject:person.fullName];

        }

        //8
        CFRelease(addressBook);
    } else {
        //9
        NSLog(@"Error reading Address Book");
    }
    NSSortDescriptor *sorter = [[NSSortDescriptor alloc] initWithKey:@"fullName" ascending:YES];
    [self.tableData sortUsingDescriptors:[NSArray arrayWithObject:sorter]];

}

Answer 1

如果要避免添加重复项，可能最简单的方法是构建一组已经添加了某些内容的ABRecordID值，并且仅在该组中不存在联系人的情况下才添加该联系人:

self.tableData = [NSMutableArray array];
NSMutableSet *foundIDs = [NSMutableSet set];

NSArray *allContacts = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));

for (id record in allContacts) {
    ABRecordRef contactPerson = (__bridge ABRecordRef)record;
    ABRecordID recordId = ABRecordGetRecordID(contactPerson);
    if (![foundIDs containsObject:@(recordId)]) {
        Person *person = [[Person alloc] init];

        // get name

        person.firstName = CFBridgingRelease(ABRecordCopyValue(contactPerson, kABPersonFirstNameProperty)) ?: @"";
        person.lastName = CFBridgingRelease(ABRecordCopyValue(contactPerson, kABPersonLastNameProperty)) ?: @"";
        person.fullName = [NSString stringWithFormat:@"%@ %@", person.firstName, person.lastName];

        // get phones

        ABMultiValueRef phones = ABRecordCopyValue(contactPerson, kABPersonPhoneProperty);
        for (NSUInteger j = 0; j < ABMultiValueGetCount(phones); j++) {
            // I presume you meant to use mutable string and `replaceOccurrencesOfString`:

            NSMutableString *phone = [CFBridgingRelease(ABMultiValueCopyValueAtIndex(phones, j)) mutableCopy];

            [phone replaceOccurrencesOfString:@" "    withString:@""   options:0 range:NSMakeRange(0, phone.length)];
            [phone replaceOccurrencesOfString:@"("    withString:@""   options:0 range:NSMakeRange(0, phone.length)];
            [phone replaceOccurrencesOfString:@")"    withString:@""   options:0 range:NSMakeRange(0, phone.length)];
            [phone replaceOccurrencesOfString:@"+336" withString:@"06" options:0 range:NSMakeRange(0, phone.length)];

            if (j == 0)     person.mainNumber   = phone;
            else if (j==1)  person.secondNumber = phone;
        }
        CFRelease(phones);

        // add the `Person` record

        [self.tableData addObject:person];

        // add the ID for this person (and all linked contacts) to our set of `foundIDs`

        NSArray *linkedPeople = CFBridgingRelease(ABPersonCopyArrayOfAllLinkedPeople(contactPerson));
        if (linkedPeople) {
            for (id record in linkedPeople) {
                [foundIDs addObject:@(ABRecordGetRecordID((__bridge ABRecordRef)record))];
            }
        } else {
            [foundIDs addObject:@(recordId)];
        }
    }
}

CFRelease(addressBook);

NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:@"fullName" ascending:YES];
[self.tableData sortUsingDescriptors:@[descriptor]];

话虽如此，您可能还应该遍历所有链接的联系人并在其中查找电话号码。也许也可以对名称进行一些验证(例如，如果您有一个J. D. Salinger条目，而另一个有John David Salinger条目，则有一些算法可以弄清楚您要使用哪个名称)。您可以做很多事情。但是以上内容说明了一种简约的解决方案，该解决方案将联系人和任何链接的联系人添加到已找到的联系人列表中。