java - JSON解析-获取值

Question

我在解析此 JSON 时遇到问题。我在 JSONObject o 中有以下数据。我如何获取critics_score的值？

{
"total":1,"
 movies":
 [{
      "id":"770672122",
      "title":"Toy Story 3",
      "year":2010,
      "mpaa_rating":"G",
      "runtime":103,
      "critics_consensus":"Deftly blending comedy, adventure, and honest emotion, Toy   Story 3 is a rare second sequel that really works.",

      "release_dates":{"theater":"2010-06-18","dvd":"2010-11-02"},
      "ratings":
       {
                "critics_rating":"Certified Fresh",
                "critics_score":99,
                "audience_rating":"Upright", .......

谢谢

Answer 1

您可以执行以下操作:

    int criticsScore;
    try {
        criticsScore = myJsonObject.getJSONArray("movies").getJSONObject(0).getJSONObject("ratings").getInt("critics_score");
    } catch (JSONException e) {
        e.printStackTrace();
    }

编辑:假设您的 JSONObject 名为 myJsonObject。