java - Spring程序未执行

Question

我尝试执行我的第一个 Spring 应用程序，但出现错误。我是 Spring 的新手，你能帮我一下吗？我将不胜感激。这是代码

 package com.bam.springexample;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class MainApp {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        ApplicationContext context = new ClassPathXmlApplicationContext("Beans.xml");
        HelloSpring obj = (HelloSpring)context.getBean("msgid");
        obj.getMessage();
    }

}

这是 POJO 类......

package com.bam.springexample;

public class HelloSpring {
private String message;

public void getMessage() {
System.out.println("Your Message is "+ message);
}

public void setMessage(String message) {
    this.message = message;
}
}

beans.xml 是

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

   <bean id="msgid" class="com.bam.springexmple.HelloSpring">
       <property name="message" value="Hello Bamadeva Its your first Spring Program ."/>
   </bean>

</beans>

我遇到的错误是

Jun 16, 2013 10:12:22 AM org.springframework.context.support.AbstractApplicationContext prepareRefresh
INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@1608e05: display name [org.springframework.context.support.ClassPathXmlApplicationContext@1608e05]; startup date [Sun Jun 16 10:12:22 IST 2013]; root of context hierarchy
Jun 16, 2013 10:12:22 AM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
INFO: Loading XML bean definitions from class path resource [Beans.xml]
Exception in thread "main" org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [Beans.xml]; nested exception is java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:320)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:290)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:142)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:158)
    at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:184)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:112)
    at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:79)
    at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:97)
    at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:411)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:338)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:122)
    at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:66)
    at com.bam.springexample.MainApp.main(MainApp.java:13)
Caused by: java.io.FileNotFoundException: class path resource [Beans.xml] cannot be opened because it does not exist
    at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:142)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:307)
    ... 12 more

提前致谢...

将 bean.sml 放入 src 文件夹后在此处进行编辑

Caused by: org.xml.sax.SAXParseException: The processing instruction target matching "[xX][mM][lL]" is not allowed.
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
    at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.reportFatalError(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.scanPIData(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanPIData(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLScanner.scanPI(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(Unknown Source)
    at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(Unknown Source)
    at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(Unknown Source)
    at org.springframework.beans.factory.xml.DefaultDocumentLoader.loadDocument(DefaultDocumentLoader.java:78)
    at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:361)
    ... 13 more

Answer 1

未找到 beans 文件 Beans.xml。您应该将 Beans.xml 放置在类路径中。

只需右键单击 Eclipse 中的 src 文件夹，然后单击 new，然后单击 other 并创建一个新的 xml 文件。将 beans.xml 的所有代码放入该文件中。

 <bean id="helloWorld" class="com.practice.HelloWorld">
   <property name="message" value="Hello World!"/>
 </bean>

我按照上面的方式声明了 bean。

按如下方式调用 bean。

 ApplicationContext context = 
         new ClassPathXmlApplicationContext("Beans.xml");

  HelloWorld obj = (HelloWorld) context.getBean("helloWorld");

这对我有用。我可以获取消息的值。