java - 如何根据 map 结果过滤流

Question

我有要通过流迭代的对象列表。我需要根据.map方法的结果转换所有不为null的对象。现在，我没有收到错误消息，但是原始列表（incomingRecords）没有被过滤。为了说明我要实现的目标，这是我的伪代码：

List<records> filteredRecords = incomingRecords.stream()
            //checkRecords either returns an object or a null -> has been repeatedly tested
            .map(record -> checkRecords(anotherList, record))
            //filter null records
            .filter(record from .map != null)
            .collect(Collectors.toList());

Answer 1

List<records> filteredRecords = 
               incomingRecords.stream()
                              .map(record -> checkRecords(anotherList, record))
                              .filter(record -> record != null)     
                              .collect(Collectors.toList());