java - 尝试检测 if 语句中的字符

Question

我在检测 if 语句中的 CHAR 时遇到了一些麻烦。我有一个分数整数，我将其放入字符串中，然后从该字符串中，我制作了一个字符数组。我的问题是，当我尝试检测字符的数字时，它返回“Error.png”。

请帮助我:)

代码:

    scoreString = "" + score;
    System.out.println(scoreString + "  -  " + scoreString.length());
    scoreA = scoreString.toCharArray();
    for(int counter = 0; counter < scoreString.length(); counter++){
            Texture drawT;
            if(scoreA[counter] == 0) drawT = i0;
            else if(scoreA[counter] == 1) drawT = i1;
            else if(scoreA[counter] == 2) drawT = i2;
            else if(scoreA[counter] == 3) drawT = i3;
            else if(scoreA[counter] == 4) drawT = i4;
            else if(scoreA[counter] == 5) drawT = i5;
            else if(scoreA[counter] == 6) drawT = i6;
            else if(scoreA[counter] == 7) drawT = i7;
            else if(scoreA[counter] == 8) drawT = i8;
            else if(scoreA[counter] == 9) drawT = i9;
            else drawT = error;
            MainClass.batch.draw(drawT, 5 + (9 * counter), 95);
    }

Answer 1

scoreA[counter] == 1 将字符与数值 1 进行比较，这是不正确的。 '1' 与 1 不同。事实上，'1' 实际上等于十六进制的 31。使用类似的东西:

if(scoreA[counter] == '0') drawT = i0;
else if(scoreA[counter] == '1') drawT = i1;
//continue on

我显然包含了一个简短的片段，但这应该足够了。