java - 使通知可点击且不可销毁

Question

我尝试创建一个通知，通过单击该通知来启动 Activity ，并且您无法将其滑开。

NotificationCompat.Builder mBuilder =
                new NotificationCompat.Builder(this)
                .setLargeIcon(BitmapFactory.decodeResource(getResources(), R.drawable.ic_launcher))
                .setSmallIcon(R.drawable.ic_launcher)
                .setContentTitle("DroidSchool")
                .setContentText("DroidSchool l\u00E4uft im Hintergrund...");

        Intent intent = new Intent(this, MainActivity.class);
        PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent, Intent.FLAG_FROM_BACKGROUND);

        NotificationManager mNotificationManager =
                (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
        
        int mId = 1234567890;
        mNotificationManager.notify(mId, mBuilder.build());

使用上面的代码，会显示通知，但当我单击它时没有任何反应，您可以将其滑开。

Answer 1

要保留通知，这样用户就无法以任何方式点击它，请添加此标志

Notification mNotification = mBuilder.build();
notification.flags = Notification.FLAG_NO_CLEAR;
mNotificationManager.notify(mId, notification);

要启动 Activity ，您必须为您的 Intent 使用此标志

Intent intent = new Intent(this, MainActivity.class);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, intent, 0);