Java十进制到二进制转换错误

Question

我现在正在做一个数字系统代码，在我的decimalToBinary上，每当我输入一个十进制数时，无论它是什么十进制数，它总是将其转换为1。代码在这里。

public static void decimalToBinary() {

        do {    
            System.out.println("Enter your decimal number");
            numDecimal = input.nextInt();

            if (numDecimal < 0) {
                System.out.println("Enter a valid number!");
            }

        } while (numDecimal < 0);

        int intNum = Integer.valueOf(numDecimal);

        int counter = 0;

        binaryVal[counter++] = intNum % 2;
        intNum = intNum/2;

        for (int i = counter-1; i >= 0; i--) {
            System.out.println("Your binary number is " + binaryVal[i]);

        }

    }

Answer 1

您在进行转换时错过了一个循环。下面是工作代码

public static void decimalToBinary() {
        int numDecimal = 0;
        Scanner input = new Scanner(System.in);
        int[] binaryVal = new int[100];
        do {    
            System.out.println("Enter your decimal number");
            numDecimal = input.nextInt();

            if (numDecimal < 0) {
                System.out.println("Enter a valid number!");
            }

        } while (numDecimal < 0);

        int intNum = Integer.valueOf(numDecimal);

        int counter = 0;
        while(intNum >0){
             binaryVal[counter++] = intNum % 2;
             intNum = intNum/2;
        }

        System.out.println("Your binary number is :");

        for (int i = counter-1; i >= 0; i--) {
             System.out.print("" + binaryVal[i]);

        }

        input.close();

    }