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java - 滑动过渡可返回,但按后退按钮不会返回

转载 作者:行者123 更新时间:2023-12-01 18:36:20 25 4
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滑动时,返回的转换有效,但当我按下后退按钮时,转换在 Android 操作系统中不起作用。

我使用过react-navigation v4 https://reactnavigation.org/docs/en/getting-started.html

export const navStack = (screenName) => createStackNavigator({
Screen1,
Screen2,
Screen3
}, {
initialRouteName: screenName,
defaultNavigationOptions: {
...TransitionPresets.SlideFromRightIOS,
headerStyleInterpolator: HeaderStyleInterpolators.forUIKit,
headerShown: false,
gestureEnabled: true
}
});
const AppTabNavigator = createBottomTabNavigator({
TabScreen1: {
screen: navStack("Screen1")
},
TabScreen2: {
screen: AnyScreen
},
}, {
initialRouteName: "TabScreen1",
backBehavior: "none",
tabBarOptions: {
showLabel: false
}
});
export const App = createAppContainer(AppTabNavigator);

最佳答案

嗨,我想是因为你设置了 backBehavior: "none"
只需尝试将其设置为 backBehavior: "initialRoute"backBehavior: "history" 它会根据您的要求将您重定向回或初始阶段尝试

关于java - 滑动过渡可返回,但按后退按钮不会返回,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60033842/

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