java - 为什么注释 Digit 2 之后的语句被标记为 "unreachable"？

Question

在下面的代码中，''Digit 2 之后的语句被标记为不可访问。为什么？

while(true){
    System.out.println("Welcome to Pi Conquest!");
    System.out.println("Name as many digits of Pi as you can");
    System.out.println("If you get an error you restart");
    System.out.println("Only includes up to 100 digits of Pi");
    System.out.println("---------------------------------------");
    System.out.println("");

    Scanner keyboard = new Scanner(System.in);

    //Digit 1
    System.out.println("Stats:");
    System.out.println("Number of Digits Entered: 0");
    System.out.println("Digits Entered: 3.");
    System.out.println("Enter the first digit of Pi. (Starting with decimals)");

    int digit1 = keyboard.nextInt();
    if(digit1==1){
        System.out.println("Correct, enter the next digit.");
        continue;
    }else{
        System.out.println("Incorrect, restarting.");
        break;
    }

    //Digit 2     <--------------------------------------- next statement marked unreachable
    System.out.println("Stats:");
    System.out.println("Number of Digits Entered: 1");
    System.out.println("Digits Entered: 3.1");

    int digit2 = keyboard.nextInt();
    if(digit2==4){
        System.out.println("Correct, enter the next digit.");
        continue;
    }else{
        System.out.println("Incorrect, restarting.");
        break;
    }
}

Answer 1

因为在之前的if ，或者以 continue 结尾的分支或以 break 结尾的分支将被执行。

这两条指令都会导致当前迭代结束，因此无法执行更多代码。