java - 如何错误处理数组中重复的学生 ID

Question

请帮助我了解如何防止在 ID 重复的情况下插入学生。我试图了解如何在不导入任何内容的情况下进行操作，但我不介意您分享您获得的任何内容，以便我可以学习。谢谢

I tried looping over every object and checking studentArray.getID() if it matches, but I can't seem to get the output right. I also tried storing every ID into another array and comparing both arrays though I think I have to use nested for loop and it broke all my code. I also couldn't get to figure out how I can just set ID to 1, then add 1 to a max of 10 since studentArray[10] is 10. So this code is the cleanest I could provide.

int size = studentArray.length;
System.out.print("Insert Student ID: ");
int ID = sc.nextInt();
System.out.print("Insert Student Name: ");
String name = sc.next();
System.out.print("Insert Student Age: ");
int age = sc.nextInt();
Student student1 = new Student(name,age,ID);
studentArray[size] = student1;
size++;
System.out.print("\nStudent Inserted!\n");

Answer 1

现在，由于您不应该使用集合，您可以做的是迭代您的 studentArray 来检查当前 ID 是否已存在于数组中。如果不存在则插入，否则跳过它。以下代码片段可以提供帮助:

 int size = studentArray.length;
 System.out.print("Insert Student ID: ");
 int ID = sc.nextInt();
 System.out.print("Insert Student Name: ");
 String name = sc.next();
 System.out.print("Insert Student Age: ");
 int age = sc.nextInt();
 int i=0
 for(;i<size;i++){
 if(studentArray[i].ID==ID)
   break;
    }
 if(i==size){
 Student student1 = new Student(name,age,ID);    
 studentArray[size] = student1;
 size++;
 System.out.print("\nStudent Inserted!\n");
  }
 else{
  System.out.print("\nStudent with the given ID is already present in the array!\n");
  }