iphone - 在OBJ-C中将完整字母转换为数字

Question

我正在尝试将字母转换为数字或整数字符串。我可以这样做，但是我想知道是否有更好的方法？我必须将4个字母转换为相应的数字，所以我用字母创建了一个NSMutableArray，然后执行此操作，即读取一个字符串，然后一次将其拉开。

编辑:所以，如果我的味精是“MNOP”，我想要的字符串是“13141516”

 alphabetArray = [[NSMutableArray alloc] init];
[alphabetArray insertObject:@"0" atIndex:0];
[alphabetArray insertObject:@"A" atIndex:1];
[alphabetArray insertObject:@"B" atIndex:2];
[alphabetArray insertObject:@"C" atIndex:3];
[alphabetArray insertObject:@"D" atIndex:4];
[alphabetArray insertObject:@"E" atIndex:5];
[alphabetArray insertObject:@"F" atIndex:6];
[alphabetArray insertObject:@"G" atIndex:7];
[alphabetArray insertObject:@"H" atIndex:8];
[alphabetArray insertObject:@"I" atIndex:9];
[alphabetArray insertObject:@"J" atIndex:10];
[alphabetArray insertObject:@"K" atIndex:11];
[alphabetArray insertObject:@"L" atIndex:12];
[alphabetArray insertObject:@"M" atIndex:13];
[alphabetArray insertObject:@"N" atIndex:14];
[alphabetArray insertObject:@"O" atIndex:15];
[alphabetArray insertObject:@"P" atIndex:16];
[alphabetArray insertObject:@"Q" atIndex:17];
[alphabetArray insertObject:@"R" atIndex:18];
[alphabetArray insertObject:@"S" atIndex:19];
[alphabetArray insertObject:@"T" atIndex:20];
[alphabetArray insertObject:@"U" atIndex:21];
[alphabetArray insertObject:@"V" atIndex:22];
[alphabetArray insertObject:@"W" atIndex:23];
[alphabetArray insertObject:@"X" atIndex:24];
[alphabetArray insertObject:@"Y" atIndex:25];
[alphabetArray insertObject:@"Z" atIndex:26];

NSRange range1 = NSMakeRange(0, 1);
NSRange range2 = NSMakeRange(1, 1);
NSRange range3 = NSMakeRange(2, 1);
NSRange range4 = NSMakeRange(3, 1);


NSString *letter1 = [msg substringWithRange:range1];  
NSString *letter2 = [msg substringWithRange:range2];
NSString *letter3 = [msg substringWithRange:range3]; 
NSString *letter4 = [msg substringWithRange:range4];

NSString *msgAsInt = [[NSString alloc]
             initWithFormat:@"%d%d%d%d",
             [alphabetArray  indexOfObject:letter1 ],
             [alphabetArray  indexOfObject:letter2 ],
             [alphabetArray  indexOfObject:letter3 ],
             [alphabetArray  indexOfObject:letter4 ]];

任何建议都很好。我还没有测试过，但是看起来还可以

谢谢，
缺口

Answer 1

如果您只想“message as int”，请执行以下操作(假设为UTF-8):

NSMutableString *msgAsInt = [[NSMutableString alloc] init];
for (int i = 0; i < msg.length; i++)
    [msgAsInt appendFormat:@"%02d", [msgAsInt characterAtIndex:i] - 'A'];

另外，如果要以后恢复消息，最好在 02之前添加该 %d。