java - Json 中的特殊字符

Question

我使用了一个网络服务，但我对它没有足够的控制权，所以我必须解析它返回的内容!这是解析部分:

        HttpResponse getResponse =  httpclient.execute(httpPost);  
        HttpEntity returnEntity = getResponse.getEntity();
        is = returnEntity.getContent();
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"), 128);
        StringBuilder sb = new StringBuilder();

        String line = null;
        while ((line = reader.readLine()) != null)
        {
            sb.append(line + "\n");
        }
        String result = sb.toString();
        result = result.replaceAll("^\"(.*)\"$","$1");
        JSONObject jObject = new JSONObject(result); //this line throws error

最后一行异常(exception):

org.json.JSONException: Expected literal value at character 1 of {\r\n  \"xUserPW\": \"EmU7cU\"\r\n}

结果字符串是:

{\r\n  \"xUserPW\": \"EmU7cU\"\r\n}

如何防止此异常？

Answer 1

and the result String is : {\r\n \"xUserPW\": \"dStT0T\"\r\n}

这不是有效的 json 格式。 Web服务是否返回json？您不能简单地将\n 附加到接收到的数据并对其进行转换。

HttpResponse getResponse =  httpclient.execute(httpPost);  
    HttpEntity returnEntity = getResponse.getEntity();
    is = returnEntity.getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"), 128);
    StringBuilder sb = new StringBuilder();

    String line = null;
    while ((line = reader.readLine()) != null)
    {
        sb.append(line);
    }
    JSONObject jObject = new JSONObject(sb.toString());

不应出现错误