java - 如何从响应中提取 json 数据 - Java

Question

我正在尝试从 Json 字符串中提取数据，该字符串是通过仅使用 Java 代码的响应获得的。我在这里发布我的 Java 代码。

输出:

Entering into while loop
[{"name":"Frank","food":"pizza","quantity":3}]

这是我的 Java 代码。

public void receive() 
{    
System.out.println("Entering into sendNote method");   
try {
// make json string,
String json = "{\"name\":\"Frank\",\"food\":\"pizza\",\"quantity\":3}";
// send as http get request
URL url1 = new URL("http://myurl/file.php?usersJSON="+userList);
URLConnection conn1= url1.openConnection();
//I am receiving exactly what I have sent....
BufferedReader rd = new BufferedReader(new InputStreamReader(conn1.getInputStream()));
String line;
while ((line = rd.readLine()) != null) 
{
System.out.println("Entering into while loop");
System.out.println(line);// line contains the received json parameters
//I want to enter the recieved parameters into my database
//
//
//
//I need the solution right here....
}
rd.close();
} 
catch (Exception e) 
{
System.out.println("Error Occured while receiving");
e.printStackTrace();
}
}

谢谢!!!!

@安库尔:这是我尝试过的方法，

@Lahiru Prasanna，@ankur-singhal非常感谢。!!

Answer 1

我认为您成功获得了 HttpResponse。这里称为响应的变量是 HttpResponse。

        // Could do something better with response.
        StatusLine statusLine = response.getStatusLine();

        if (statusLine.getStatusCode() == 200) {
            HttpEntity entity = response.getEntity();
            InputStream content = entity.getContent();
        StringBuilder   builder = new StringBuilder();
            BufferedReader reader = new BufferedReader(
                new InputStreamReader(content));
            String line;
            try {
                while ((line = reader.readLine()) != null) {
                    builder.append(line);
                }
                content.close();

            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            try {
            JSONObject  jsonObject = new JSONObject(builder.toString());
            } catch (JSONException e) {
                System.out.println("Error parsing data " + e.toString());
            }

        }
    } catch (Exception e) {
        System.out.println("Error:  " + e.toString());
        System.out.println( "" + e.toString());
        System.out.println("" + e.toString());
    } 

重要的是永远不要使用字符串进行 json 操作。

您可以像这样从 jsonObject 检索数据

String name = jsonObject.getString("name");