java - 如何读取带有空格的文本文件 android java

Question

当我知道我的文件包含时，如何将带有空格的文本文件读取到 int 数组中

"22 23 29 1 "

诸如此类

private String readFromFile() {

    String ret = "";

    try {
        InputStream inputStream = openFileInput("mywords.txt");

        if ( inputStream != null ) {
            InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
            BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
            String receiveString = "";
            StringBuilder stringBuilder = new StringBuilder();

            while ( (receiveString = bufferedReader.readLine()) != null ) {
                stringBuilder.append(receiveString);
            }

            inputStream.close();
            ret = stringBuilder.toString();
        }
    }
    catch (FileNotFoundException e) {
        Log.e("login activity", "File not found: " + e.toString());
    } catch (IOException e) {
        Log.e("login activity", "Can not read file: " + e.toString());
    }

    return ret;
}

到目前为止我一直用它来阅读

Answer 1

对于 "22 23 29 1 " 即带空格的整数，请尝试以下代码:

String ret="22 23 29 1 ";
ret=ret.trim();
String tok[]=ret.split(" ");
for(String s:tok) {
    System.out.println(s);
}

输出:

22
23
29
1

如果您需要，可以使用 Integer.parseInt() 将 string 解析为 integer 。