java - 老虎机 - 输出不正确

Question

代码运行良好。然而有一个小问题，如果后两个数字相同，则代码表示没有数字匹配。例如:

0 2 2没有匹配的数字再玩一次？ (是/否？)

显然应该说:

0 2 2两个数字匹配再玩一次？ (是/否？)

如何更改代码以实现此目的？

谢谢

import java.util.Random;
import java.util.Scanner;

public class SlotMachine {
public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int slotOne;
    int slotTwo;
    int slotThree;
    String userResponse;

    do{

        Random randomNumbers = new Random();

        slotOne = randomNumbers.nextInt(10);  
        slotTwo= randomNumbers.nextInt(10);  
        slotThree = randomNumbers.nextInt(10);  


        System.out.println(slotOne + " " + slotTwo +  " " + slotThree + " " );  
        if (slotOne != slotTwo && slotOne != slotThree) 
        { 
            System.out.println("No numbers match");  
        }
        else if (slotOne == slotTwo && slotOne == slotThree) 
        { 
            System.out.println("All three match - jackpot"); 
        } 
        else
        { 
            System.out.println("Two numbers match"); 
        }       

        System.out.print("Play again? (Y/N?)");
        userResponse = scan.next();
    }

    while (userResponse.equalsIgnoreCase("Y"));

    do{
        if(userResponse.equalsIgnoreCase("N"))

        {
            System.out.print("Thank You.");
            userResponse = scan.next();
        }
        else if (!userResponse.equalsIgnoreCase("Y"))
        {
            System.out.print("Play again? (Y/N?)");
            userResponse = scan.next();
        }
    }
    while (!userResponse.equalsIgnoreCase("Y"));

    scan.close();

}
}

Answer 1

我建议你计算匹配项，a == b、b == c和a == c，例如

System.out.println(slotOne + " " + slotTwo +  " " + slotThree + " " );  
int count = 0;
if (slotOne == slotTwo) count++;
if (slotOne == slotThree) count++;
if (slotTwo == slotThree) count++;
if (count == 3) {
    System.out.println("All three match - jackpot");
} else if (count > 0) {
    System.out.println("Two numbers match");
} else {
    System.out.println("No numbers match");
}