java - 使用 System.out 中的方法不起作用？

Question

我的任务是完成几个目标，我要读取一个文件，我相信我做得正确，然后从该整数文件中将其放入一个数组中。它不会让我编译代码，它至少会出现错误。那么，如何打印出 min 的方法呢？

public class jlrogers2 {

public static void reader(int[] arr) throws FileNotFoundException { 

 Scanner scanner = new Scanner(new FileReader("numbers.txt"));
    int i = 0;

    while(scanner.hasNextInt())
    {
        arr[i++] = scanner.nextInt();
    }


}

public static int minnimum(int[] arr){

int smallest =arr[0];

for (int i = 1; i>arr.length; i++){
        if (arr[i] > smallest)
        {
            smallest= arr[i];
            System.out.println(smallest);
        }
    }
    return smallest;
}
 public static void main(String [] args) throws FileNotFoundException   
{  


    Scanner in = new Scanner (System.in);
    System.out.println("Enter 1 for max index value.\nEnter 2 for min index   value.\nEnter 3 to search for an index value.\n"
            + "Enter 4 for display all index's\nEnter 5 for numbers in a range.\nEnter 6 to exit menu. ");

    int number = in.nextInt();

    if(number==6){
        System.out.println("Thank you for being awesome");
    }

    if (number==5){
    System.out.println(minnimum(smallest))  // here is my issue }


}  

}

Answer 1

更改for (int i = 1; i>arr.length; i++)至for (int i = 0; i<arr.length; i++)而且你找到最小的逻辑也是错误的。实际上你正在寻找最大的。

要找到最小的，请将其写为

if(arr[i] < smallest )里面for循环

将主要更改为

 public static void main(String [] args) throws FileNotFoundException   
{  

 Scanner in = new Scanner (System.in);
 System.out.println("Enter 1 for max index value.\nEnter 2 for min index   value.\nEnter 3 to search for an index value.\n"
        + "Enter 4 for display all index's\nEnter 5 for numbers in a range.\nEnter 6 to exit menu. ");

 int number = in.nextInt();
 int arr[] = new int [200];//change this according to the requirement
 if(number==6){
    System.out.println("Thank you for being awesome");
}

if (number==5){
  reader(arr); 
 System.out.println(minnimum(arr)); 
 }
}