java - 解释一下这个比较器？

Question

我知道 int maxLength 返回列表中最长单词的长度，但我认为 return arg0.length() - arg1.length(); 应该返回类似 -1 0 或 1 的内容。那么这些值如何设置为最后的 .length()

 int maxLength = Collections.max(lst, new Comparator<String>() { //get length of longest word using Collections.max comparator
            @Override
            public int compare(String arg0, String arg1) {
                return arg0.length() - arg1.length();
            }
        }).length();

Answer 1

这个

arg0.length() - arg1.length()

将返回一个整数，表示arg0与arg1的比较情况，如果为0，则在逻辑比较中两者相等，如果为-x，则arg1比arg1大x，如果为x，则arg0比arg1大x比 arg1

could you explain the .length() part as well? how is a 1 set to .length() at the end. – FatFockFrank just now

此语句类似于

String longestString = Collections.max(lst, new Comparator<String>() { //get length of longest word using Collections.max comparator
            @Override
            public int compare(String arg0, String arg1) {
                return arg0.length() - arg1.length();
            }
        });

int maxLength = longestString.length();