java - Android 中奇怪的 NumberFormatException

Question

它看起来像整数，但它不能用 Integer.parse() 解析，我该如何修复它？

 int a= Integer.parseInt(lhs.getViewCount());

 Caused by: java.lang.NumberFormatException: Invalid int: "6125635424"
        at java.lang.Integer.invalidInt(Integer.java:138)
        at java.lang.Integer.parse(Integer.java:378)
        at java.lang.Integer.parseInt(Integer.java:366)
        at java.lang.Integer.parseInt(Integer.java:332)
        at com.youtubetracker.adapters.MyChannelListAdapter$1.compare(MyChannelListAdapter.java:46)
        at com.youtubetracker.adapters.MyChannelListAdapter$1.compare(MyChannelListAdapter.java:37)

Answer 1

始终使用BigInteger过长并漂浮。

BigInteger value= new BigInteger(lhs.getViewCount());

您可以将该值转换为 int 、 long 或 float。

表单 Java 文档 intValue()

Converts this BigInteger to an int. This conversion is analogous to a narrowing primitive conversion from long to int as defined in section 5.1.3 of The Java™ Language Specification: if this BigInteger is too big to fit in an int, only the low-order 32 bits are returned. Note that this conversion can lose information about the overall magnitude of the BigInteger value as well as return a result with the opposite sign.