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java - Android - 单击按钮以使用 ListView 显示 Activity 时应用程序崩溃

转载 作者:行者123 更新时间:2023-12-01 18:16:37 24 4
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我在网上找到了这段代码,并决定在我的应用程序上尝试一下(如果适用)。单击该按钮时,当数据库中的所有数据都显示在 ListView 中时,它应该显示一个 Activity 。

代码如下:

MainActivity.java

public class MainActivity extends ListActivity {

private ProgressDialog pDialog;

// URL to get contacts JSON
private static String url = "http://api.androidhive.info/contacts/";

// JSON Node names
private static final String TAG_CONTACTS = "contacts";
private static final String TAG_ID = "id";
private static final String TAG_NAME = "name";
private static final String TAG_EMAIL = "email";
private static final String TAG_ADDRESS = "address";
private static final String TAG_GENDER = "gender";
private static final String TAG_PHONE = "phone";
private static final String TAG_PHONE_MOBILE = "mobile";
private static final String TAG_PHONE_HOME = "home";
private static final String TAG_PHONE_OFFICE = "office";

// contacts JSONArray
JSONArray contacts = null;

// Hashmap for ListView
ArrayList<HashMap<String, String>> contactList;

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main5);

contactList = new ArrayList<HashMap<String, String>>();

ListView lv = getListView();

// Listview on item click listener
lv.setOnItemClickListener(new OnItemClickListener() {

@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
// getting values from selected ListItem
String name = ((TextView) view.findViewById(R.id.name))
.getText().toString();
String cost = ((TextView) view.findViewById(R.id.email))
.getText().toString();
String description = ((TextView) view.findViewById(R.id.mobile))
.getText().toString();

// Starting single contact activity
Intent in = new Intent(getApplicationContext(),
SingleContactActivity.class);
in.putExtra(TAG_NAME, name);
in.putExtra(TAG_EMAIL, cost);
in.putExtra(TAG_PHONE_MOBILE, description);
startActivity(in);

}
});

// Calling async task to get json
new GetContacts().execute();
}

/**
* Async task class to get json by making HTTP call
* */
private class GetContacts extends AsyncTask<Void, Void, Void> {

@Override
protected void onPreExecute() {
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(MainActivity5.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();

}

@Override
protected Void doInBackground(Void... arg0) {
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();

// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);

Log.d("Response: ", "> " + jsonStr);

if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);

// Getting JSON Array node
contacts = jsonObj.getJSONArray(TAG_CONTACTS);

// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);

String id = c.getString(TAG_ID);
String name = c.getString(TAG_NAME);
String email = c.getString(TAG_EMAIL);
String address = c.getString(TAG_ADDRESS);
String gender = c.getString(TAG_GENDER);

// Phone node is JSON Object
JSONObject phone = c.getJSONObject(TAG_PHONE);
String mobile = phone.getString(TAG_PHONE_MOBILE);
String home = phone.getString(TAG_PHONE_HOME);
String office = phone.getString(TAG_PHONE_OFFICE);

// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();

// adding each child node to HashMap key => value
contact.put(TAG_ID, id);
contact.put(TAG_NAME, name);
contact.put(TAG_EMAIL, email);
contact.put(TAG_PHONE_MOBILE, mobile);

// adding contact to contact list
contactList.add(contact);
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("ServiceHandler", "Couldn't get any data from the url");
}

return null;
}

@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
MainActivity5.this, contactList,
R.layout.list_item, new String[] { TAG_NAME, TAG_EMAIL,
TAG_PHONE_MOBILE }, new int[] { R.id.name,
R.id.email, R.id.mobile });

setListAdapter(adapter);
}

}

}

然后这是按钮所在的类:

public class MainActivity3Activity extends Activity implements OnClickListener {

Button ViewGradesActivity;
Button ClassScheduleActivity;
Button CalendarOfActivitiesActivity;
Button AccountBalanceActivity;
Button StudentProfileActivity;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main_activity3);


ShowMainActivity= (Button) findViewById(R.id.mainactbutton);
ShowMainActivity.setOnClickListener(this);

ClassScheduleActivity = (Button) findViewById(R.id.classSched);
ClassScheduleActivity.setOnClickListener(this);

CalendarOfActivitiesActivity = (Button) findViewById(R.id.activities);
CalendarOfActivitiesActivity.setOnClickListener(this);

AccountBalanceActivity = (Button) findViewById(R.id.balance);
AccountBalanceActivity.setOnClickListener(this);

StudentProfileActivity = (Button) findViewById(R.id.profile);
StudentProfileActivity.setOnClickListener(this);

}

@Override
public void onClick(View view) {
switch(view.getId()) {
//this is to show the activity with the list view
case R.id.mainactbutton:
startActivity(new Intent(this,MainActivity5.class));
break;
case R.id.classSched:
startActivity(new Intent(this,classSchedule.class));
break;
case R.id.activities:
startActivity(new Intent(this,CalendarOfActivities.class));
break;
case R.id.balance:
startActivity(new Intent(this,AccountBalance.class));
break;
case R.id.profile:
startActivity(new Intent(this,StudentProfile.class));
break;
}
}

}

因此,每当我单击 mainactbutton 时,应用程序就会崩溃。我应该怎么办? ListView 的 Activity 是否有问题?

感谢您的帮助。

编辑:现在我已经编辑了 list 文件并添加了 MainActivity5,应用程序仍然崩溃,日志如下:

at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:600)
at dalvik.system.NativeStart.main(Native Method)
Caused by: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list'
at android.app.ListActivity.onContentChanged(ListActivity.java:243)
at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:277)
at android.app.Activity.setContentView(Activity.java:1881)
at com.example.kreshiathea.myfirstapp.MainActivity5.onCreate(MainActivity5.java:52)
at android.app.Activity.performCreate(Activity.java:5122)
at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1081)
at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2270)

这是我的 ListView :

activity_main5.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical">
<!-- Main ListView
Always give id value as list(@android:id/list)
-->
<ListView
android:id="@android:id/list"
android:layout_width="fill_parent"
android:layout_height="wrap_content"/>

</LinearLayout>

            

最佳答案

have you declared this activity in your AndroidManifest.xml?

您使用的每项 Activity 都必须在 list 中声明

      <activity
android:name="com.example.kreshiathea.myfirstapp.MainActivity5"
android:label="@string/app_name"
android:id="@android:id/list"
>
</activity>

关于java - Android - 单击按钮以使用 ListView 显示 Activity 时应用程序崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29138297/

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