ios - 在iOS中解析Google翻译JSON

Question

从Google Translate解析JSON的最佳方法是什么。

到目前为止，我有:

NSString *urlText = [NSString stringWithFormat:@"https://www.googleapis.com/language/translate/v2?key=%@&target=%@&q=%@",
                      key, target, selectedWord];

NSLog(@"%@", urlText);

NSURL *url = [NSURL URLWithString:urlText];


NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];
[request setHTTPMethod:@"GET"];

NSURLResponse *response;
NSError *error;
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

NSString *result = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];

结果是:

{
 "data": {
  "translations": [
   {
    "translatedText": "Provincial capital",
     "detectedSourceLanguage": "de"
   }
  ]
 }

}

然后我:

if(data != nil){
NSDictionary *dic = [NSJSONSerialization
                                    JSONObjectWithData:data
                                    options:kNilOptions
                                    error:&error];
NSArray *dataObj = dic[@"data"];

NSLog(@"%@", dataObj);
}
else {
NSLog(@"ERR");
}

产生:

{
translations =     (
            {
        detectedSourceLanguage = de;
        translatedText = "Provincial capital";
    }
);
}

然后，我该如何从检测到的SourceLanguage中获取“de”，并从translationText中获取“省会”？
我尝试创建第二个数组:

NSArray *arr2 = [dataObj valueForKey:@"detectedSourceLanguage"];

没有成功

Answer 1

调用dic[@"data"];会给您一个字典，而不是数组。因此，您需要:

NSDictionary *data = dic[@"data"];

现在您需要翻译数组:

NSArray *translations = data[@"translations"];

那是一系列字典:

for (NSDictionary *translation in translations) {
    NSString *detectedLanguage = translation[@"detectedSourceLanguage"];
    NSString *translatedText = translation[@"translatedText"];
}

一次将问题分解成一步即可获得所需的数据。