Java 字符无法正确识别

Question

我不明白为什么下面的代码:

public Image getLetter(String letterToGet)
{
    System.out.println("é" == "e");

    System.out.println("Received: " + letterToGet);

    if("\u00e9" == letterToGet.toLowerCase()); {
        letterToGet = "SPECIALACCTAIGUESPECIAL";
    }
    if("\u00e8" == letterToGet.toLowerCase()) {
        letterToGet = "SPECIALACCTGRAVESPECIAL";
    }

    System.out.println("searching for " + letterToGet + " in the hashmap");
    return languageMap.get(letterToGet.toLowerCase());
}

可以返回以下输出

Traduction following ArrayList: [e, é, è]
Received: e
searching for SPECIALACCTAIGUESPECIAL in the hashmap
Received: é
searching for SPECIALACCTAIGUESPECIAL in the hashmap
Received: è
searching for SPECIALACCTAIGUESPECIAL in the hashmap

按照这个逻辑，为什么这一行会返回 false？

System.out.println("\u00e9" == "e");

Answer 1

意外输出的原因是第一个 if 后面多了一个分号。

目前，您已经

if("\u00e9" == letterToGet.toLowerCase()); {
    letterToGet = "SPECIALACCTAIGUESPECIAL";
}

其中对 letterToGet 的赋值超出了 if 的范围，因此无论 letterToGet 的值如何，它都会运行.