java - Spring session + Spring Web 套接字。根据 session ID 向特定客户端发送消息

Question

我已关注Quetion1和 Quetion2从堆栈溢出向特定客户端发送消息，基于其sessionId，但找不到成功。

下面是我的示例 RestController 类

@RestController
public class SpringSessionTestApi {

@Autowired
public SimpMessageSendingOperations messagingTemplate;

@MessageMapping("/messages")
public void greeting(HelloMessage message, SimpMessageHeaderAccessor headerAccessor) throws Exception {

    String sessionId  = (String) headerAccessor.getSessionAttributes().get("SPRING.SESSION.ID");
    messagingTemplate.convertAndSendToUser(sessionId,"/queue/test",message, createHeaders(sessionId));

   }

private MessageHeaders createHeaders(String sessionId) {
    SimpMessageHeaderAccessor headerAccessor = SimpMessageHeaderAccessor.create(SimpMessageType.MESSAGE);
    headerAccessor.setSessionId(sessionId);
    headerAccessor.setLeaveMutable(true);
    return headerAccessor.getMessageHeaders();
   }
}

Session Id:当客户端发送createSession请求时，会生成新的spring sessionId，并将其存储在MongoDB中。之后，当客户端发送 Web 套接字连接请求时，会收到相同的 sessionId，该 sessionId 按预期存储在 mongoDb 中。直到这一切都工作正常。

现在我的工作是根据 sessionId 将响应发送回客户端。为此，我有以下网络套接字类:

@Configuration
@EnableScheduling
@EnableWebSocketMessageBroker
public class WebSocketConfig extends
    AbstractSessionWebSocketMessageBrokerConfigurer<ExpiringSession> {

@Override
protected void configureStompEndpoints(StompEndpointRegistry registry) {
    registry.addEndpoint("/messages");
}

public void configureMessageBroker(MessageBrokerRegistry registry) {
    registry.enableSimpleBroker("/queue");
    registry.setApplicationDestinationPrefixes("/app");
   }
}

我用来连接的示例客户端代码是:

function connect() {

stompClient = Stomp.client('ws://localhost:8016/messages');
stompClient.debug = null;

stompClient.connect({}, function (frame) {
    setConnected(true);
    console.log('Connected: ' + frame);
    stompClient.subscribe('/user/queue/test', function (greeting) {
        console.log("Hello "+greeting);
        console.log("Greeting body "+JSON.parse(greeting.body));

    });
});
}

请帮忙，我哪里做错了？提前致谢!

Answer 1

如果您像这样使用/user channel ，请尝试按所述 here 传递用户。 .

@MessageMapping("/messages")
public void greeting(HelloMessage message, SimpMessageHeaderAccessor headerAccessor, Principal principal) 
    throws Exception {
    messagingTemplate.convertAndSendToUser(principal.getName(), "/queue/test", message);
}