gpt4 book ai didi

java - 同步有什么问题

转载 作者:行者123 更新时间:2023-12-01 18:12:12 24 4
gpt4 key购买 nike

代码出了什么问题,我的线程没有同步:我在下面的示例中具有线程将调用的同步打印方法,但输出仍然显示线程在访问打印方法时未同步。请参阅下面的输出。

主类

public class ExecutorTester {

public static void main(String[] args) {

PrinterRunnable pr = new PrinterRunnable();
ExecutorService excutor = Executors.newFixedThreadPool(20);
//ExecutorService excutor = Executors.newSingleThreadExecutor();
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);

excutor.shutdown();

for(int i =0; i<5;i++)
System.out.println("In Main Thread : "+i);
}
}

线程类

public class PrinterRunnable implements Runnable {

@Override
public void run() {
for(int i =0; i<5;i++){
//System.out.println("In Thread class" +i);
Printer p = new Printer();
p.print(i);
}
}
}

其他类

public class Printer {

public synchronized void print(int i){
System.out.println("Entered Thread: "+Thread.currentThread().getId());
System.out.println("In thread: "+Thread.currentThread().getId()+"count::"+i );
System.out.println("Exit Thread: "+Thread.currentThread().getId());
}
}

控制台输出(见下面线程13和11都进入了!!!)

Entered Thread: 13
Entered Thread: 11
In thread: 11count::0
Exit Thread: 11
Entered Thread: 11
In thread: 11count::1
Exit Thread: 11
In thread: 13count::0
Exit Thread: 13
Entered Thread: 13
In thread: 13count::1
Exit Thread: 13
........
........
........

最佳答案

当关键字synchronized 是方法签名的一部分时,如

public synchronized void print(int i)

那么此同步引用调用此方法的实例。每次您想要打印某些内容时,您都会创建一个新的 Printer 实例。

为了达到预期的效果,您必须在一个公共(public)对象上进行同步。例如,这可以这样实现:

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class ExecutorTester
{
public static void main(String[] args)
{
PrinterRunnable pr = new PrinterRunnable(new Object());
ExecutorService excutor = Executors.newFixedThreadPool(20);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);
excutor.submit(pr);

excutor.shutdown();

for (int i = 0; i < 5; i++)
System.out.println("In Main Thread : " + i);
}
}

class PrinterRunnable implements Runnable
{
private final Object monitor;

PrinterRunnable(Object monitor)
{
this.monitor = monitor;
}

@Override
public void run()
{
for (int i = 0; i < 5; i++)
{
// System.out.println("In Thread class" +i);
Printer p = new Printer(monitor);
p.print(i);
}
}
}

class Printer
{
private final Object monitor;

Printer(Object monitor)
{
this.monitor = monitor;
}

public void print(int i)
{
synchronized (monitor)
{
System.out.println("Entered Thread: " +
Thread.currentThread().getId());
System.out.println("In thread: " +
Thread.currentThread().getId() + " count::" + i);
System.out.println("Exit Thread: " +
Thread.currentThread().getId());
}
}
}

但是,当然,这是一个过于务实的草图。在实际应用程序中,您应该仔细考虑要在哪个对象上同步。

关于java - 同步有什么问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32159818/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com