Java URL openStream 抛出异常

Question

我有以下代码，但是当我运行它时出现异常

"SocketTimeoutException" at openStream.

代码:

String urlStr = "https://www.nse-india.com/live_market/dynaContent/live_watch/get_quote/getHistoricalData.jsp?symbol=SCHNEIDER&series=EQ&fromDate=01-01-2020&toDate=29-02-2020&datePeriod=&hiddDwnld=true";

URL urlConn = new URL(urlStr);
InputStream in = urlConn.openStream();

当我从浏览器执行相同的 URL 时，它工作正常。

Answer 1

服务器查找两个请求 header ，以下代码有效

        String urlStr = "https://www.nse-india.com/live_market/dynaContent/live_watch/get_quote/getHistoricalData.jsp?symbol=SCHNEIDER&series=EQ&fromDate=01-01-2020&toDate=29-02-2020&datePeriod=&hiddDwnld=true";

        URL url = new URL(urlStr);
        URLConnection conn = url.openConnection();
        conn.setRequestProperty("accept-language", "en-US,en;q=0.9");
        conn.setRequestProperty("user-agent", "MyJavaApp");
        InputStream in = conn.getInputStream();