Java gradle build不重新编译源文件

Question

我有一个 gradle java 项目。我最近将源文件重新组织到 dub 文件夹中。

原来我所有的源文件都在文件夹中...

project_root/src/main/java

现在我有 Foo.java 类...

project_root/src/main/java/folderA

我有 Bar.java 类...

project_root/src/main/java/folderB

Bar 依赖于 Foo。当我更改 Foo 类时，Bar 类不会重新编译。因为 Foo 已经改变，类 Bar 应该有编译错误，但它们没有命中。

我的build.gradle文件如下...

apply plugin: 'java'

// Use maven repository
repositories {
    mavenCentral()
    google()
}

dependencies {
    implementation 'org.eclipse.jetty:jetty-servlet:9.4.19.v20190610'
    implementation 'org.eclipse.jetty:jetty-client:9.4.19.v20190610'
    implementation 'mysql:mysql-connector-java:8.0.16'
    implementation 'org.apache.commons:commons-dbcp2:2.7.0'
    implementation 'org.jdbi:jdbi3-core:3.10.1'
    implementation 'com.google.firebase:firebase-admin:6.11.0'
    compile 'com.google.apis:google-api-services-oauth2:v1-rev155-1.25.0'
    // implementation 'com.google.gms:google-services:4.3.3'

    // https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-databind
    compile group: 'com.fasterxml.jackson.core', name: 'jackson-databind', version: '2.0.1'
    compile group: 'org.reflections', name: 'reflections', version: '0.9.11'

    compile project('chesslib')
    runtime files('../../chesslib/build/libs/chesslib-1.1.12.jar')
}

task runServer(type: JavaExec) {
   classpath = sourceSets.main.runtimeClasspath 
   main = 'ChessServer'
} 

task runClient(type: JavaExec) {
   classpath = sourceSets.main.runtimeClasspath 
   main = 'ChessClient'
   standardInput = System.in // without this, using Scanner on System.in won't work
}

task runCLITestApp(type: JavaExec) {
   classpath = sourceSets.main.runtimeClasspath 
   main = 'CLITestApp'
   standardInput = System.in
}

Answer 1

您遇到了 Gradle 中增量编译的限制，如 the documentation 中所述。 :

If there is a mismatch in the package declaration and the directory structure of source files (e.g. package foo vs location bar/MyClass.java), then incremental compilation can produce broken output. Wrong classes might be recompiled and there might be leftover class files in the output.

因此建议使用经典的包到文件夹结构或禁用增量编译:

compileJava {
  options.incremental = false
}